Answer:
The magnitude of the torque is 263.5 N.
Explanation:
Given that,
Applied force = 31 N
Distance from the axis = 8.5 m
She applies her force perpendicularly to a line drawn from the axis of rotation
So, The angle is 90°
We need to calculate the torque
Using formula of torque
Where, F = force
d = distance
Put the value into the formula
Hence, The magnitude of the torque is 263.5 N.
The answer is 2.66 x 10^8 J.
The player would need to use a greater force and take less
<h2>
Answer: The half-life of beryllium-15 is 400 times greater than the half-life of beryllium-13.</h2>
Explanation:
The half-life of a radioactive isotope refers to its decay period, which is the average lifetime of an atom before it disintegrates.
In this case, we are given the half life of two elements:
beryllium-13:
beryllium-15:
As we can see, the half-life of beryllium-15 is greater than the half-life of beryllium-13, but how great?
We can find it out by the following expression:
Where is the amount we want to find:
Finally:
Therefore:
The half-life of beryllium-15 is <u>400 times greater than</u> the half-life of beryllium-13.
Answer:
77.8s
Explanation:
Let d distance between the asteroid and space tug
So;d=Xtug+Xspace
Xtug=VtT+0.5atT^2
Xspace=VsT+0.5asT^2
Since Vt=Vs=0 initial velocity
Then
d=0.5(atT^2+asT^2)
T^2( at+as)=2d
T=√(2d/at+as)
But force F = mass M*acceleration a
Hence at=Ft/mt ,as=Fs/ms
But note Ft=F=Fs since the Same force acts on it
Hence T=√( 2d/F(1/mt+1/Ms))
T=√(2*493/366(1/3460+1/6430)
T=√(986/0.1627)=√(6060.195)=77.8s