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ivann1987 [24]
2 years ago
10

Can someone please answer this, ill give you brainliest Would be very appreciated.

Physics
2 answers:
dimaraw [331]2 years ago
7 0

Answer:

True

Explanation:

Water is present in each of the four major Earth systems (hydrosphere, atmosphere, geosphere, and biosphere) and readily moves from one to another. For example, water in the hydrosphere can evaporate to become part of the atmosphere.

<em>Please give brainliest !! :)</em>

3241004551 [841]2 years ago
6 0

Answer:

<u>True</u>

Explanation:

  • The spheres of the Earth are : <u>Biosphere, Hydrosphere, Geosphere, and Atmosphere</u>
  • Water travels through liquid form only (known as water itself) through 3 spheres
  • It travels through the atmosphere in gas form (vapor) or liquid form itself as rain
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The flywheel of a steam engine runs with a constant angular velocity of 190 rev/min. When steam is shut off, the friction of the
Ivanshal [37]

Answer:

(a) \alpha = - 1.32\ rev/m^{2}

(b) \theta = 13674\ rev

(c) \alpha_{tan} = 8.75\times 10^{- 4}\ m/s^{2}

(d) a = 22.458\ m/s^{2}

Solution:

As per the question:

Angular velocity, \omega = 190\ rev/min

Time taken by the wheel to stop, t = 2.4 h = 2.4\times 60 = 144\ min

Distance from the axis, R = 38 cm = 0.38 m

Now,

(a) To calculate the constant angular velocity, suing Kinematic eqn for rotational motion:

\omega' = \omega + \alpha t

omega' = final angular velocity

\omega = initial angular velocity

\alpha = angular acceleration

Now,

0 = 190 + \alpha \times 144

\alpha = - 1.32\ rev/m^{2}

Now,

(b) The no. of revolutions is given by:

\omega'^{2} = \omega^{2} + 2\alpha \theta

0 = 190^{2} + 2\times (- 1.32) \theta

\theta = 13674\ rev

(c) Tangential component does not depend on instantaneous angular velocity but depends on radius and angular acceleration:

\alpha_{tan} = 0.38\times 1.32\times \frac{2\pi}{3600} = 8.75\times 10^{- 4}\ m/s^{2}

(d) The radial acceleration is given by:

\alpha_{R} = R\omega^{2} = 0.32(80\times \frac{2\pi}{60})^{2} = 22.45\ rad/s

Linear acceleration is given by:

a = \sqrt{\alpha_{R}^{2} + \alpha_{tan}^{2}}

a = \sqrt{22.45^{2} + (8.75\times 10^{- 4})^{2}} = 22.458\ m/s^{2}

5 0
3 years ago
two soccer players, mary and jane, begin running from nearly the same point at the same time. mary runs in an easterly direction
goblinko [34]

The time taken before the two soccer players are 24.7 m apart is 3 seconds.

Velocity of Jane relative to marry is 4.4 m/s in y-direction and 6.95 m/s in x direction.

The distance between Jane and Mary after 4.08 seconds is 33.58 m.

<h3>Resultant velocity of Mary and Jane</h3>

Vertical component of the velocity;

Jane: Vy1 = V sinθ

Vy1 = 5.07 m/s  x  sin(60.2)

Vy1 = 4.4 m/s

Horizontal components of the velocity;

Jane: Vx1 = V cos θ

Vx1 = 5.07 m/s  x  cos60.2

Vx1 = 2.52 m/s

mary: Vx2 = 4.43 m/s

total horizontal components of the velocity = 4.43 m/s + 2.52 m/s = 6.95 m/s

<h3>Resultant velocity</h3>

V = √Vy² + Vx²

V = √(4.4² + 6.95²)

V = 8.23 m/s

<h3>Time taken before they are 24.7 m apart</h3>

t = 24.7 m / 8.23 m/s

t = 3 seconds

Velocity of Jane relative to marry is 4.4 m/s in y-direction and 6.95 m/s in x direction.

<h3>Distance between Jane and Mary after 4.08 seconds</h3>

d = vt

d = 8.23 m/s  x 4.08 s

d = 33.58 m

Learn more about relative velocity here: brainly.com/question/17228388

#SPJ1

5 0
1 year ago
Electricity cost 10p how much will it cost to use a 85w laptop and a 60w lamp for an hour
Reil [10]

Answer:

Explanation:

usually electricity is sold in the units of kWh, which I will ASSUME is the case here.

85 W (1 kW/1000W)(1hr)(10 p) = 0.85p

60 W (1 kW/1000W)(1hr)(10 p) = <u>0.60p</u>

together they would cost           1.45 p

which would be rounded down to 1 p

7 0
3 years ago
What are ways that ordinary people can help to keep antibiotic resistance from getting worse?
just olya [345]

Answer:

they can take the right amount of antibiotics prescribed and at the right time as told by the doctor.

3 0
3 years ago
A centripetal force of 210 N acts on a 1,600-kg satellite moving with a speed of 5,500 m/s in a circular orbit around a planet.
Dafna1 [17]

Answer:

<h2>230476.19km</h2>

Explanation:

Step one:

given

Force F= 210N

mass m= 1600kg

velocity v=5500m/s

Step two

Required is the radius r

the expression for the force is

F_c = \frac{mv^2}{r}

substitute

210=1600*5500^2/r

cross multiply we have

210r=48400000000

divide both side by 210

r=230476190.476m

r=230476.19km

4 0
3 years ago
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