Explanation:
The principle of cross-cutting relationships states that a fault or intrusion is younger than the rocks that it cuts through. The fault labeled "E" cuts through all three sedimentary rock layers (A, B,and C) and also cuts through the intrusion (D). So the fault must be the youngest formation that is seen and known of.
Answer:
Explanation:
Given
---- Altitude of container in Denver
-- Surface Area of the container lid
--- Air pressure in Denver
--- Air pressure in New Orleans
<em>See comment for complete question</em>
Solving (a): The expression for
Force is calculated as:
The force in New Orleans is:
Since the inside pressure is half the pressure at sea level, then:
Where
--- Standard Pressure
Recall that:
This gives:
Solving (b): The value of
In (a), we have:
Where
So, we have:
Answer:
3 x 10^ 8 m/s
Explanation:
Speed of wave = wavelength/time period
= 30000/0.0001
= 300000000 m/s
Answer:
0.785 m/s
Explanation:
Hi!
To solve this problem we will use the equation of motion of the harmonic oscillator, <em>i.e.</em>
- (1)
- (1)
The problem say us that the spring is released from rest when the spring is stretched by 0.100 m, this condition is given as:
Since cos(0)=1 and sin(0) = 0:
We get
Now it say that after 0.4s the weigth reaches zero speed. This will happen when the sping shrinks by 0.100. This condition is written as:
Since
This is the same as:
We know that cosine equals to -1 when its argument is equal to:
(2n+1)π
With n an integer
The first time should happen when n=0
Therefore:
π = 0.4ω
or
ω = π/0.4 -- (2)
Now, the maximum speed will be reached when the potential energy is zero, <em>i.e. </em>when the sping is not stretched, that is when x = 0
With this info we will know at what time it happens:
The first time that the cosine is equal to zero is when its argument is equal to π/2
<em>i.e.</em>
And the velocity at that time is:
But sin(π/2) = 1.
Therefore, using eq(2):
And so:
Answer:
μ = 0.66, therefore if it compiesy with the regulations
Explanation:
Let's solve this exercise in part, let's start by finding with kinematics the acceleration of man
y = v₀ t + ½ a t²
as it starts from rest the initial velocity is zero
y = ½ a t²
a =
a =\frac{2 \ 4.38}{1.21^2}
a = 6.46 m / s²
Now let's use Newton's second law,
Axis y
N- W = 0
N = W
N = m g
X axis
on this axis the man exerts a backward force and by the law of action and reaction the floor exerts a forward force of the same magnitude, this forward force is the friction force.
fr = m a
the friction force has an expression
fr = my N
let's substitute
μ mg = m a
μ = a / g
let's calculate
μ = 6.46 / 9.8
μ = 0.66
therefore if you comply with the regulations