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sleet_krkn [62]
3 years ago
10

An object is accelerates for 10 seconds at 8 m/s after a force of 300 joules is applied to it. . What is the mass?

Physics
2 answers:
Arisa [49]3 years ago
8 0

Answer:

37.5

Explanation:

m = F ÷ a; F ÷ a = m

300 ÷ 8 = 37.5

Hope this helps,

♥<em>A.W.E.</em><em><u>S.W.A.N.</u></em>♥

Veronika [31]3 years ago
8 0

The mass of the object for the given problem is 9.375 kg

<u>Explanation:</u>

As the force is given in terms of energy, this means the work done on the object to move it has been given as 300 J. As the work done on any system is equal to the variations in the object's kinetic energy.

As the object's kinetic energy at rest will be zero due to zero initial velocity, the work done will be equal to the final kinetic energy of the object in moving after application of this force. It is known that kinetic energy is the energy required by the object to be in motion.

Also it is known that the kinetic energy required to move an object will be directly proportionate to the product of mass of the object and the velocity attained by the object. Thus,

             \text { kinetic energy }=\frac{1}{2} \times \text { Mass of the object } \times \text { (velocity of the object) }^{2}

So,

             \text { Mass of the object }=\frac{2 \times \text { Kinetic energy }}{\text { (velocity of the object) }^{2}}

             \text { Mass of the object }=\frac{2 \times 300 \mathrm{J}}{8 \times 8 \mathrm{m}^{2} \mathrm{s}^{-2}}=\frac{600 \mathrm{kgm}^{2} \mathrm{s}^{-2}}{64 \mathrm{m}^{2} \mathrm{s}^{-2}}=9.375 \mathrm{kg}

Thus, the mass of the object is 9.375 kg.

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A 5g block rests on a rough horizontal table a rope attached to the block is pulled with a force of 11N to the left as a result
mr Goodwill [35]

<u>Complete Question:</u>

A 5 g block rests on a rough horizontal table. A rope is attached to the block and is pulled with a force of 11 N to the left. As a result, the block accelerates at 2 m/s^2. What is the kinetic friction between the block and the table?

<u>Correct Answer:</u>

The kinetic frictional force between the block and the rough surface is 10.99 N towards the right side.

F_{net} = - 0.01 N is the resulting net force causing an acceleration of 2\ m/s^2 to the left

<u>Explanation:</u>

According to the first law of motion by Newton, any object can be moved only when an unbalanced force acts on the object. As the block is placed on a rough horizontal table, then the applied force should be greater than the kinetic frictional force between the object and the rough surface, in order to move that block.

So, it is known that the net force acting on the block will be the difference between the force acting on the object due to the rope and the frictional force acting on the object.

F_{net} = F_{rope} -F_{friction}

So, the force acting on the block due to rope is given as 11 N. The net force should be equal to the product of mass and acceleration of the object, as per Newton's second law of motion. As the mass of the block is 5 g and the acceleration is given as 2\ m/s^2.

F_{net} = Mass * Acceleration = \frac{5}{1000} * -2  = -0.01 N

Since, the net force and the force due to rope is acting opposite to the gravitational force ,

-0.01 = -11 - Frictional force

Frictional force = -11 + 0.01 = -10.99 N

Thus, the kinetic frictional force between the block and the rough surface is 10.99 N towards the right side.

F_{net} = - 0.01 N is the resulting net force causing an acceleration of 2\ m/s^2 to the left

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Three kids are riding on a snow sled traveling horizontally without friction at 19.8 m/s. The masses of Kid A, B, and C are 42.8
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Answer:

34.6 m/s

Explanation:

From conservation of momentum, the sum of initial and final momentum are equal. Momentum is a product of mass and velocity. Initial mass will be 42.8+31.5+25.9=100.2 kg

Final mass will be 31.5+25.9=57.4 kg

From formula of momentum

M1v1=m2v2

Making v2 the subject of the formula then

V2=\frac {M1v1}{m2}

Substitute 100.2 kg for M1, 19.8 m/s fkr v1 and 57.4 kg for m2 then

V2=\frac {100.2 kg\times 19.8 m/s}{57.4 kg}=34.56376 m/s\approx 34.6 m/s

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It should be noted that this process can be consciously controlled by the person who speaks (or sings), since the variation in the intensity of the sound of the voice depends on the strength of the breath.

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