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ella [17]
3 years ago
8

The pilot of an airplane traveling 180km/h wants to drop supplies to flood victims isolated on a patch of land 160 m below. The

supplies should be dropped how many seconds before the plane is directly overhead?
Physics
1 answer:
gulaghasi [49]3 years ago
4 0
I think it's 21 that's what I got when I was on that answer
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Multiply the following three numbers and report your answer to the correct number of significant figures: 0.020cm x 50cm x 11.1c
Neko [114]

Answer:11.1

Explanation:

Three significant figures

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What does the signal word then accomplish in these sentences
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An alpha particle travels at a velocity of magnitude 550 m/s through a uniform magnetic field of magnitude 0.045T. (An alpha par
creativ13 [48]

Answer:

the force is perpendicular to the speed, it is a type of force that changes the direction of the speed, as in the uniform circular motion te, but does not change its modulus.

Explanation:

The magnetic force is given by the expression

    F = q v x B

The bold are vectors, where v is the velocity and B is the magnetic field, the product is the cross product whose result is a vector perpendicular to the two vectors (v and B)

From the above, the force is perpendicular to the speed, it is a type of force that changes the direction of the speed, as in the uniform circular motion te, but does not change its modulus.

   

Even when the change in direction is real and is caused by a centripetal force

For there to be a change in the velocity modulus there must be a force parallel to the velocity direction, generally a force in electrical

3 0
3 years ago
A 55 kg person moves at the constant speed of 7 m/s along a straight stretch of track for 20s. How far does he travel in this ti
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By definition,
Distance = Speed * Time

Therefore the distance traveled is
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6 0
4 years ago
A 25 kg box of textbooks rests on a loading ramp that makes an angle α with the horizontal. The coefficient of kinetic friction
Lunna [17]

Up until the moment the box starts to slip, the static friction is maximized with magnitude <em>f</em>, so that by Newton's second law,

• the net force acting on the box parallel to the ramp is

∑ <em>F</em> = <em>mg</em> sin(<em>α</em>) - <em>f</em> = 0

where <em>mg</em> sin(<em>α</em>) is the magnitude of the parallel component of the box's weight; and

• the net force acting perpendicular to the ramp is

∑ <em>F</em> = <em>n</em> - <em>mg</em> cos(<em>α</em>) = 0

where <em>n</em> is the magnitude of the normal force and <em>mg</em> cos(<em>α</em>) is the magnitude of the perpendicular component of weight.

From the second equation we have

<em>n</em> = <em>mg</em> cos(<em>α</em>)

and <em>f</em> = <em>µn</em> = <em>µmg</em> cos(<em>α</em>), where <em>µ</em> is the coefficient of static friction. Substituting these into the first equation gives us

<em>mg</em> sin(<em>α</em>) = <em>µmg</em> cos(<em>α</em>)   ==>   <em>µ</em> = tan(<em>α</em>)   ==>   <em>α</em> = arctan(0.35) ≈ 19.3°

8 0
3 years ago
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