<h2>
Answer:</h2>
(a) 10N
<h2>
Explanation:</h2>
The sketch of the two cases has been attached to this response.
<em>Case 1: The box is pushed by a horizontal force F making it to move with constant velocity.</em>
In this case, a frictional force 
is opposing the movement of the box. As shown in the diagram, it can be deduced from Newton's law of motion that;
∑F = ma -------------------(i)
Where;
∑F = effective force acting on the object (box)
m = mass of the object
a = acceleration of the object
∑F = F -
m = 50kg
a = 0 [At constant velocity, acceleration is zero]
<em>Substitute these values into equation (i) as follows;</em>
F - = m x a
F - = 50 x 0
F - = 0
F = -------------------(ii)
<em>Case 2: The box is pushed by a horizontal force 1.5F making it to move with a constant velocity of 0.1m/s²</em>
In this case, the same frictional force is opposing the movement of the box.
∑F = 1.5F -
m = 50kg
a = 0.1m/s²
<em>Substitute these values into equation (i) as follows;</em>
1.5F - = m x a
1.5F - = 50 x 0.1
1.5F - = 5 ---------------------(iii)
<em>Substitute </em><em> = F from equation (ii) into equation (iii) as follows;</em>
1.5F - F = 5
0.5F = 5
F = 5 / 0.5
F = 10N
Therefore, the value of F is 10N
<em />
Answer:increased
Explanation:
It is given that elevator speed is increasing while moving upward i.e.its acceleration is increasing .
This causes the apparent to be increased if measured using weighing machine.
considering upward direction to be positive
N-mg=ma
N=m(g+a)
where N=Normal reaction=Apparent weight
a=acceleration of Elevator
thus you feel as if your weight is increased.
Explanation:
1. Movement of water, food and mineral salts in plants
2. Absorption of water by towels when wiping our bodies
3. It is used to absorb ink using a blotting paper or tissue
Answer:
(a) The velocity of the bullet and B after the first impact is 4.4554 m/s.
(b) The velocity of the carrier is 0.40872 m/s.
Explanation:
(a) To solve the question, we apply the principle of conservation of linear momentum as follows.
we note that the distance between B and C is 0.5 m
Then we have
Sum of initial momentum = Sum of final momentum
0.03 kg × 450 m/s = (0.03 kg + 3 kg) × v₂
Therefore v₂ = (13.5 kg·m/s)÷(3.03 kg) = 4.4554 m/s
The velocity of the bullet and B after the first impact = 4.4554 m/s
(b) The velocity of the carrier is given as follows
Therefore from the conservation of linear momentum we also have
(m₁ + m₂)×v₂ = (m₁ + m₂ + m₃)×v₃
Where:
m₃ = Mass of the carrier = 30 kg
Therefore
(3.03 kg)×(4.4554 m/s) = (3.03 kg+30 kg) × v₃
v₃ = (13.5 kg·m/s)÷ (33.03 kg) = 0.40872 m/s
The velocity of the carrier = 0.40872 m/s.
