raise each side to base 4
simplify
using the law of logarithms
=>
y=62
A two-digit number is twice the sum of its digit. If the tens digit is 7 less than the unit digit, find the number.
Let x= the unit digit
Then y= the tens digit
<span>And 10y+x= the number
</span>x+y= the sum of the digits
<span>Now we are told that 10y+x=2(x+y) ------1st equation </span>
<span>We are also told that y=x-7 ----------- 2nd Equation </span>
<span>So our equations to solve are: </span>
(1) 10y+x=2(x+y)
<span>(2) y=x-7
</span>
Hope it helps
I think it would be like how many times does 5 go into 48.. and that would be 9 and 3/5
1. diginity
2.require
3.tuition
Answer:
-450
-90
270
Step-by-step explanation: Just did it on edgen-uity
