Ask question

Ask question

All categories

3 years ago

8

What was the original volume of a gas if heating it from 22k to 85k produced a volume of 3.8 liters?

1 answer:

mel-nik [20]3 years ago

3 0

Answer: the original volume was 0.98L

Explanation:

V1 =?

T1 = 22k

V2 = 3.8L

T2 = 85k

V1 /T1 = V2 /T2

VI/22 = 3.8/85

V1 = 22 x (3.8/85)

V1 = 0.98L

You might be interested in

Valence electrons<br> Fill in the blanks

IgorC [24]

Answer:

Valence electrons or outer electrons are most important as they participate in bonding. The octet rule states that atoms gain, lose, or share valence electrons to have filled energy levels.. this gives atoms a stable configuration like that of the nearest noble gas.

6 0

3 years ago

Lewis dot diagram for the Cs1+ ion

creativ13 [48]

Answer:

$Cs^+$

Explanation:

Cesium Lewis dot structure would look like this:

·Cs, because it only has one valence electron. But, since it has a plus, that means we lost an electron. So, we have to get rid of the dot and you have:

$Cs^+$

7 0

2 years ago

What is an oxidation reaction?

kow [346]

<h3>Definition:</h3>

A reaction when an atom or compound loses one or more electrons.

It is a reaction is a type of chemical reaction that involves a transfer of electrons between two species.

Oxidation is gain of oxygen

<h3>For Example:</h3>

Fe + O2 —(H2O)—> Fe2O3

7 0

2 years ago

Mixture with two or more substances that are evenly mixed

sertanlavr [38]

A homogeneous mixture, the substances are uniformly distributed throughout the mixture

8 0

3 years ago

A mileage test is conducted for a new car model. Thirty randomly selected cars are driven for a month and the mileage is measure

Leni [432]

Answer: $(27.81,\ 29.39)$

Explanation:

Given : Sample size : n= 30 , it means it is a large sample (n≥ 30), so we use z-test .

Significance level : $\alpha: 1-0.95=0.05$

Critical value: $z_{\alpha/2}=1.96$

Sample mean : $\overline{x}=28.6$

Standard deviation : $\sigma=2.2$

The formula to find the confidence interval is given by :-

$\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}$

i.e. $28.6\pm (1.96)\dfrac{2.2}{\sqrt{30}}$

i.e. $28.6\pm 0.787259889321$

$\approx28.6\pm 0.79=(28.6-0.79,28.6+0.79)=(27.81,\ 29.39)$

Hence, the 95% confidence interval for the mean mpg in the entire population of that car model = $(27.81,\ 29.39)$

4 0

3 years ago