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Vadim26 [7]
3 years ago
10

Which salt is the most common found in ocean water?

Chemistry
2 answers:
Ivenika [448]3 years ago
7 0

Answer:

Sodium chloride

Explanation:

There are several salts in seawater, but the most abundant is ordinary table salt or sodium chloride (NaCl). Sodium chloride, like other salts, dissolves in water into its ions, so this is really a question about which ions are present in the greatest concentration. Sodium chloride dissociates into Na+ and Cl- ions.

11111nata11111 [884]3 years ago
5 0
D sodium chloride sodium is salt
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A sample of oxygen gas at a pressure of 1.19 atm and a temperature of 24.4 °C, occupies a volume of 18.7 liters. If the gas is a
mihalych1998 [28]

Answer:

\boxed {\boxed {\sf 0.757 \ atm}}

Explanation:

We are asked to find the pressure of a gas given a change in volume. Since the temperature remains constant, we are only concerned with volume and pressure. We will use Boyle's Law, which states the volume is inversely proportional to the pressure. The formula for this law is:

P_1V_1= P_2V_2

Initially, the oxygen gas occupies a volume of 18.7 liters at a pressure of 1.19 atmospheres.

1.19 \ atm * 18.7 \ L = P_2V_2

The gas expands to a volume of 29.4 liters, but the pressure is unknown.

1.19 \ atm * 18.7 \ L = P_2 * 29.4 \ L

We are solving for the new pressure, so we must isolate the variable P_2. It is being multiplied by 29.4 liters. The inverse operation of multiplication is division. Divide both sides of the equation by 29.4 L.

\frac {1.19 \ atm * 18.7 \ L}{29.4 \ L} =\frac{ P_2 * 29.4 \ L}{29.4 \ L}

\frac {1.19 \ atm * 18.7 \ L}{29.4 \ L} =P_2

The units of liters cancel.

\frac {1.19 \ atm * 18.7 }{29.4 } =P_2

\frac {22.253}{29.4 } \ atm = P_2

0.7569047619 \ atm =P_2

The original measurements all have 3 significant figures, so our answer must have the same. For the number we calculated, that is the thousandth place. The 9 in the ten-thousandth place to the right of this place tells us to round the 6 up to a 7.

0.757 \ atm \approx P_2

The pressure of the gas sample is approximately <u>0.757 atmospheres.</u>

3 0
3 years ago
Read 2 more answers
A clear colorless liquid in an open beaker was heated to boiling. The liquid began to boil at 110°C, and as vapors escaped, the
Vaselesa [24]

Omitted options and they are

a) pure compound.

b. pure element.

c. pure substance.

d. homogeneous solution.

e. heterogeneous solution

Answer:d. homogeneous solution.

Explanation:

Pure substances or  elements or  compounds have a definite and sharp melting or boiling point, Any substance that is not pure is impure and will have different temperature of melting or boiling points.

To this effect, the clear colorless liquid cannot be a Pure substance, element or compound.

We can therefore say that the clear colorless liquid would be a homogeneous solution because a homogeneous solution is a mixture of constituents which completely mixes together such that each constituents cannot be seen with naked eye, When heated to boiling, each constituent in the mixture will give different boiling points.

A heterogeneous Solution, too is a mixture but contains constituents that can be seen and not a clear colourless solution.

Therefore  On the basis of this information, we can say that the material in the beaker was a Homogeneous solution

8 0
4 years ago
Explain how you would make 500ml of a 0.100 m naoh solution
icang [17]
Molar mass NaOH =23+16+1=40 g/mol
<span> 0.100 M= 0.100 mol/L
</span>500 ml=0.500 L
0.500L*0.100 mol/L=0.0500 mol NaOH we need to prepare 500 ml solution
0.0500 mol NaOH*40g/1mol=2 g NaOH we need to prepare 500 ml solution
we need  2 g NaOH, dissolve it in small amount of water, and dilute it with water up to 500 mL
3 0
3 years ago
In which way does a balanced chemical equation demonstrate the conservation of matter?​
Alika [10]

Answer:

Every chemical equation adheres to the law of every conservation of mass and the states of matter cannot be created or destroyed  

Explanation:

5 0
3 years ago
Which statement is incorrect regarding the reaction of benzene with an electrophile? View Available Hint(s) A) The carbocation i
Leno4ka [110]

Answer:

The carbocation intermediate reacts with a nucleophile to form the addition product.

Explanation:

The reaction of benzene with an electrophile is an electrophillic substitution reaction. Here the electrophile replaces hydrogen. There is no formation of carbocation as intermediate in the reaction. Infact there is transition state where the electorphile attacks on benzene ring and at the same time the hydrogen gets removed from the benzene. So a transition carbocation is formed.

The general mechanism is shown in the figure.

i) Attack of the electrophile on the benzene (which is the nucleophile)

ii) The carbocation intermediate loses a proton from the carbon bonded to the electrophile.

iii) the carbocation formation is the rate determining step.

iv) There is no formation of addition product.

Thus the wrong statement is

The carbocation intermediate reacts with a nucleophile to form the addition product.

3 0
4 years ago
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