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Vadim26 [7]
3 years ago
10

Which salt is the most common found in ocean water?

Chemistry
2 answers:
Ivenika [448]3 years ago
7 0

Answer:

Sodium chloride

Explanation:

There are several salts in seawater, but the most abundant is ordinary table salt or sodium chloride (NaCl). Sodium chloride, like other salts, dissolves in water into its ions, so this is really a question about which ions are present in the greatest concentration. Sodium chloride dissociates into Na+ and Cl- ions.

11111nata11111 [884]3 years ago
5 0
D sodium chloride sodium is salt
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Upon combustion, a 1.3109 g sample of a compound containing only carbon, hydrogen, and oxygen produces 3.2007 g<img src="https:/
Ivenika [448]

Answer:

The answer to your question is:   C₃H₃O  This is my answer.

Explanation:

Data

Sample = 1.3109 g

CxHyOz

CO₂ = 3.2007 g

H₂O = 1.3102 g

Empirical formula = ?

MW CO2 = 44 g

MW H2O = 18 g

For Carbon

                                     44 g -------------------- 12 g

                                     3.2007 g ------------    x

                                      x = (3.2007 x 12) / 44

                                      x = 0.8729 g of Carbon

                                     12 g of C --------------  1 mol

                                     0.8729 g --------------  x

                                     x = (0.8729 x 1) / 12

                                     x = 0.0727 mol of Carbon

For Hydrogen

                                 18 g ---------------------- 1 g

                              1.3102 g -------------------  x

                                   x = (1.3102 x 1) / 18

                                  x = 0.0727 g of Hydrogen                                      

                                  1 g ------------------------ 1 mol

                                  0.0727g ----------------  x

                                  x = (0.0727 x 1)/1

                                  x = 0.0727 mol of Hydrogen

For oxygen

                    g of Oxygen = g of sample - g of Carbon - g of hydrogen

                    g of Oxygen = 1.3109 - 0.8709 - 0.0727

                    g of Oxygen = 0.3673

                                  16 g of Oxygen ------------- 1 mol of O

                                  0.3673 g ---------------------   x

                                   x = (0.3673 x 1)/ 16

                                   x = 0.0230 mol of Oxygen

Divide by the lowest number of moles

Carbon              0.0727 / 0.023  = 3.1  ≈ 3

Hydrogen         0.0727 / 0.023 = 3.1  ≈ 3

Oxygen             0.0230 / 0.023 = 1

                                        C₃H₃O

8 0
3 years ago
Read 2 more answers
In order to reduce the exposure to organic solvents like turpentine, some art instructors recommend the students clean brushes a
kykrilka [37]
Generally speaking, organic molecules tend to dissolve in solvents that have similar physical properties. A good rule of thumb is that "like dissolves like". Meaning, polar compounds can dissolve polar compounds and nonpolar compounds can dissolve nonpolar compounds.

To apply this to the current problem, we are told that the brushes are being cleaned with vegetable oil or mineral oil. In this case, the oils are used as solvents. In order for these solvents to be effective, the compounds they are trying to dissolve must be similar in structure and properties to other oils. Therefore, vegetable oil or mineral oil will be most effective in removing oil-based paints, as these will have the similar properties needed to dissolve in the oil solvents.
6 0
3 years ago
Suppose you are titrating a sulfuric acid solution of unknown concentration with a sodium hydroxide solution according to the eq
Inga [223]

Answer:

M_{acid}=0.0444M

Explanation:

Hello,

In this case, for the given reaction:

H _2 S O _4 + 2 N a O H \rightarrow 2 _H 2 O + N a _2 S O_ 4

We find a 1:2 molar ratio between the acid and the base respectively, for that reason, at the equivalence point we find:

2*n_{acid}=n_{base}

That in terms of concentrations and volumes we can compute the concentration of the acid solution:

2*M_{acid}V_{acid}=M_{base}V_{base}\\\\M_{acid}=\frac{M_{base}V_{base}}{2*V_{acid}}=\frac{0.697M*28.07mL}{2*220.1mL}\\ \\M_{acid}=0.0444M

Best regards.

5 0
3 years ago
Tris {(hoch2)3cnh2} is one of the most common buffers used in biochemistry. a solution is prepared by adding enough tris and 12
shusha [124]

Given that,

The concentration of TRIS = 0.30 M

The concentration of TRIS+ = 0.60 M

Kb = 1.2 x 10^-6

pKb = -log Kb = - log (1.2 x 10^-6) = 5.920

Now, by using the Hendersonn equation,

pH = pKa + log TRIS+/TRIS = 5.920 + log (0.60/0.30) = 6.221

<span>pOH=14-pH=14-6.221 = 7.779</span>

7 0
3 years ago
Read 2 more answers
What is the main function of the part labeled Y in the model?
Tanya [424]

Answer

D

Explanation

<em>the</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>D</em>

8 0
3 years ago
Read 2 more answers
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