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Novay_Z [31]
3 years ago
11

Side length of 216 cubic yards

Mathematics
2 answers:
scZoUnD [109]3 years ago
7 0

Answer:

6 yards

Step-by-step explanation:

a³ = 216

a = ∛ 216

    = <u>6 yards</u>

TEA [102]3 years ago
7 0

Answer:

6 yards

Step-by-step explanation:

The volume of a cube can be found using the following formula.

v= s^3

We know the volume is 216 cubic yards, so we can substitute 216 yd³ in for v.

216 yd^3=s^3

We want to find the side length. Therefore, we must isolate the variable, s, on one side of the equation.

s is being cubed. The inverse of cubed is the cube root. Take the cube root of both sides of the equation.

\sqrt[3]{216 yd^3}=\sqrt[3]{s^3}

\sqrt[3]{216yd^3}=s

6yd=6

The side length of the cube is 6 yards.

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I need help<br> please someone
mina [271]

Answer:

second option

Step-by-step explanation:

x - y= 28

x+y = 56

4 0
2 years ago
A bowling leagues mean score is 197 with a standard deviation of 12. The scores are normally distributed. What is the probabilit
Bond [772]

Answer:

0.281 = 28.1% probability a given player averaged less than 190.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

A bowling leagues mean score is 197 with a standard deviation of 12.

This means that \mu = 197, \sigma = 12

What is the probability a given player averaged less than 190?

This is the p-value of Z when X = 190.

Z = \frac{X - \mu}{\sigma}

Z = \frac{190 - 197}{12}

Z = -0.58

Z = -0.58 has a p-value of 0.281.

0.281 = 28.1% probability a given player averaged less than 190.

8 0
3 years ago
How many quarts of pure antifreeze must be added to 8 quarts of a 40% antifreeze solution to obtain a 60% antifreeze solution
anyanavicka [17]

Let <em>q</em> be the number of quarts of pure antifreeze that needs to be added to get the desired solution.

8 quarts of 40% solution contains 0.40 × 8 = 3.2 quarts of antifreeze.

The new solution would have a total volume of 8 + <em>q</em> quarts, and it would contain a total amount of 3.2 + <em>q</em> quarts of antifreeze. You want to end up with a concentration of 60% antifreeze, which means

(3.2 + <em>q</em>) / (8 + <em>q</em>) = 0.60

Solve for <em>q</em> :

3.2 + <em>q</em> = 0.60 (8 + <em>q</em>)

3.2 + <em>q</em> = 4.8 + 0.6<em>q</em>

0.4<em>q</em> = 1.6

<em>q</em> = 4

4 0
2 years ago
The GCF of an odd number and an even number is always even
Oxana [17]
The answer is No it is not
7 0
2 years ago
In a certain town, the amount of sulfur oxide in the air, S, in tons, is related to the town’s population, P, in people. The rel
Lady bird [3.3K]

Answer:

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

Step-by-step explanation:

Data provided in the question:

Relation between the amount of sulfur oxide in the air and the population as:

S² = 110P² + 20P + 600

Population growth rate, \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

Now,

change in sulfur oxide with time i.e \frac{\textup{dS}}{\textup{dt}}

differentiating the given relation with respect to time 't'

we have

2S\frac{\textup{dS}}{\textup{dt}} =  2\times110P\frac{\textup{dP}}{\textup{dt}}  + 20

at P = 100 and  \frac{\textup{dP}}{\textup{dt}}  = 10 people per month

we have

2S\frac{\textup{dS}}{\textup{dt}} = 2 × 110 × 100 × 10 + 20

or

2S\frac{\textup{dS}}{\textup{dt}} = 220020

or

\frac{\textup{dS}}{\textup{dt}} = \frac{\textup{220020}}{\textup{2S}}

or

Change in sulfur oxide in the air = \frac{\textup{110010}}{\textup{S}}

8 0
2 years ago
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