In Chemistry, the Periodic Table is the source of all knowledge. Look on it for the information you need.
B = 11 grams / mol
F = 19 grams / mol
This stuff has a formula of BF3.
The 3 only affects the F. There is 1 Boron and 3 florines. If you want a number to affect the Boron, use brackets. In this case, we don't.
BF3 = 11 + 3*19 = 11 + 57 = 68 grams / mol
Molar Mass BF3 = 68 grams /mol <<<< ==== answer
<u>Answer:</u>
0.00926
<u>Explanation:</u>
no. of moles = mass ÷ molar mass (RMM)
Molar mass of Al is 27.
∴ no. of moles = 0.25 ÷ 27
= 0.00926 moles (3 s.f.)
Answer:
16kg/s
Explanation:
The formula for acceleration is [ a = f/m ] where f = force and m = mass
a = 4/0.25
a = 16
Best of Luck!
Answer:
0.635 cm³
Explanation:
You divide the mass by the density of iron (7.87 g/cm³)
<em>D = m</em>/<em>V</em> Multiply both sides by V.
<em>DV = m</em> Divide both sides by D.
<em>V</em> = <em>m</em>/<em>D</em> Insert the values.
<em>V </em>= 5.00/7.87 Do the division.
<em>V</em> = 0.635 cm³
Answer:
Explanation:
The air 9% mole% methane have an average molecular weight of:
9%×16,04g/mol + 91%×29g/mol = 27,8g/mol
And a flow of 700000g/h÷27,8g/mol = 25180 mol/h
In the reactor where methane solution and air are mixed:
In = Out
Air balance:
91% air×25180 mol/h + 100% air×X = 95%air×(X+25180)
Where X is the flow rate of air in mol/h = <em>20144 mol air/h</em>
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The air in the product gas is
95%×(20144 + 25180) mol/h = 43058 mol air× 21%O₂ = 9042 mol O₂ ×32g/mol = <em>289 kg O₂</em>
43058 mol air×29g/mol <em>1249 kg air</em>
Percent of oxygen is: =<em>0,231 kg O₂/ kg air</em>
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I hope it helps!