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pychu [463]
3 years ago
10

Relative dating is used to arrange geological events, and the rocks they leave behind, in a sequence. The method of reading the

order is called strata, A. True or B. False
Chemistry
1 answer:
SashulF [63]3 years ago
3 0

<u>Answer:</u>

<em>False. The method of reading the order is called stratification and not strata.</em>

<u>Explanation:</u>

<em>Relative dating is a technique used to arrange geological events </em>in a sequential order by analyzing the rocks. Relative dating technique doesn’t give the actual date of fossils like in other <em>dating processes like carbon dating. Each rock layer is called stratum. </em>

<em>Sedimentary rocks are laid down in an order with one layer above the other. </em>Older rocks occupy the bottom position and the younger rocks occupy the top positions. <em>This is called principle of horizontality.</em>  

<em>The sideways extension of the rocks also follows this rule. </em>

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Answer:

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Explanation:

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A pulse with an amplitude of 3+ would be considered:
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If the K a Ka of a monoprotic weak acid is 7.3 × 10 − 6 , 7.3×10−6, what is the pH pH of a 0.40 M 0.40 M solution of this acid?
olga_2 [115]

Answer:

pH =3.8

Explanation:

Lets call the monoprotic weak acid HA, the dissociation equilibria in water will be:

HA + H₂O   ⇄ H₃O⁺ + A⁻    with  Ka = [ H₃O⁺] x [A⁻]/ [HA]

The pH is the negative log of the H₃O⁺ concentration, we know the equilibrium constant, Ka and the original acid concentration. So we will need to find the [H₃O⁺] to solve this question.

In order to do that lets set up the ICE table helper which accounts for the species at equilibrium:

                          HA                                   H₃O⁺                          A⁻          

Initial, M             0.40                                   0                              0

Change , M          -x                                     +x                            +x

Equilibrium, M    0.40 - x                              x                               x

Lets express these concentrations in terms of the equilibrium constant:

Ka = x² / (0.40 - x )

Now the equilibrium constant is so small ( very little dissociation of HA ) that is safe to approximate 0.40 - x to 0.40,

7.3 x 10⁻⁶ = x² / 0.40  ⇒ x = √( 7.3 x 10⁻⁶ x 0.40 ) = 1.71 x 10⁻³

[H₃O⁺] = 1.71 x 10⁻³

Indeed 1.71 x 10⁻³ is small compared to 0.40 (0.4 %). To be a good approximation our value should be less or equal to 5 %.

pH = - log ( 1.71 x 10⁻³ ) = 3.8

Note: when the aprroximation is greater than 5 % we will need to solve the resulting quadratic equation.

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