The solution would be like this for this specific problem:
First, we need to write
out the balanced reaction equation for the problem:<span>
"gaseous nitrogen with gaseous hydrogen to produce
gaseous ammonia"
gaseous nitrogen + gaseous hydrogen = gaseous ammonia
gaseous nitrogen = N2(g)
gaseous hydrogen = H2(g)
gaseous ammonia = NH3(g)
In here, I’m going to show you how to balance this from start
to finish:
N2(g) + H2(g) ↔ NH3(g) (basic, unbalanced equation that shows
reactants and product)
N2(g) + H2(g) ↔ 2NH3(g) (balances the nitrogens)
N2(g) + 3H2(g) ↔ 2NH3(g) (balances the hydrogens) =>
Balanced Equation
<span>Next, we write the Keq expression of the balanced reaction:
Keq = (∏[products]^n) /(∏[reactants]^n)
Keq = [NH3]^2 / [[N2][H2]]^3
Therefore, the correct
equilibrium constant expression is Keq = (NH3)2 / (N2)(H2)3.</span></span>
16 atoms of hydrogen and 8 atoms of oxygen
<h3>Answer:</h3>
Number of Protons = 9
Number of Neutrons = 9
Number of Electrons = 10
<h3>Explanation:</h3>
Number of Protons:
The number of protons present in any atom are equal to the atomic number of that particular atom. Hence, as the atomic number of Fluorine is 9 therefore, it contains 9 protons.
Number Neutrons:
The number of neutrons present in atom are calculated as,
# of Neutrons = Atomic Mass - # of protons
As given,
Atomic Mass = 18
# of Protons = 9
So,
# of Neutrons = 18 - 9
# of Neutrons = 9
Number of Electrons:
As we know for a neutral atom the number of electrons are exactly equal to the number of protons present in its nucleus. So, for 9 protons in neutral Fluorine atom there must be 9 electrons. But, we are given with Fluoride Ion (i.e. F⁻) so it contains one extra electron hence, it contains the total of 10 electrons respectively.