All categories

4 years ago

1.

Chemistry

2 answers:

natta225 [31]4 years ago

7 0

Answer:

1. solid

2. Energy

3. Solid

Explanation:

Please mark me with the brain thing

Aloiza [94]4 years ago

3 0

1. Solids. The particles in a solid are tightly packed together and can only vibrate from their fixed positions.
2. Energy. Adding in energy makes the particles of a substance vibrate faster, breaking the forces of attraction between them and removing energy makes the particles vibrate slower and forces of attraction forms between the particles.
3. Gas. The forces of attraction between the particles of a gas are very weak. The particles randomly and quickly move around in all directions.

You might be interested in

Determine the molarity of 50 mL of HCl solution with unknown concentration, titrated with 75 mL of 4.0 M NaOH.

DanielleElmas [232]

The answer is 6.0 M HCl

5 0

3 years ago

How many grams of sodium chloride are dissolved in 375 ml of a 0.90% saline solution?

liq [111]

Answer:

337.5 g NaCl

Explanation:

.90% saline solution = 90g saline (NaCl)/100mL water (H2O)

1. Use 375 mL to find mass

375 mL × (90 g NaCl/100 mL) = 337.5 g NaCl in 375 mL .9% saline solution

3 0

3 years ago

A motorcyclist completes a journey at an average speed of 65 mph

Andrews [41]

227.5

Hope this helps :)

8 0

3 years ago

Transfer 2-3 drops of each solution onto the indicator paper. Be sure to

alexira [117]

Answer:

0.1 M HCl pH: 1-2

0.001 M HCl pH: 3-4

0.00001 M HCl pH: 5-6

Distilled Water pH: 7

0.00001 M NaOH pH: 8-9

0.001 M NaOH pH: 10-11

0.1 M NaOH pH: 12-13

Explanation:

4 0

3 years ago

Determine the volume (in liters) of a 87.8-9 sample of OF2 gas at 307 torr and 264°C.

expeople1 [14]

Answer:

V = 177.4 L.

Explanation:

Hello there!

In this case, since this gas can be assumed as ideal due to the given data, we can use the following equation:

$PV=nRT\\\\PV=\frac{m}{MM}RT$

Thus, by solving for volume we obtain:

$V=\frac{mRT}{MM*P}$

So we can plug in the temperature in Kelvins (537 K), the pressure in atmospheres (0.404 atm) and the molar mass (54 g/mol) to obtain:

$V=\frac{87.8g*0.08206\frac{atm*L}{mol*K}*537K}{54g/mol*0.404atm}\\\\V=177.4L$

Best regards!

6 0

3 years ago