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In-s [12.5K]
3 years ago
11

Based on the ideal gas law, there is a simple equivalency that exists between the amount of gas and the volume it occupies. at s

tandard temperature and pressure (stp; 273.15 k and 1 atm, respectively), one mole of gas occupies 22.4 l of volume. what mass of methanol (ch3oh) could you form if you reacted 5.86 l of a gas mixture (at stp) that contains an equal number of carbon monoxide (co) and hydrogen gas (h2) molecules?
Chemistry
1 answer:
nordsb [41]3 years ago
4 0
<span>2.10 grams. The balanced equation for the reaction is CO + 2H2 ==> CH3OH The key thing to take from this equation is that it takes 2 hydrogen molecules per carbon monoxide molecule for this reaction. And since we've been given an equal number of molecules for each reactant, the limiting reactant will be hydrogen. We can effectively claim that we have 5.86/2 = 2.93 l of hydrogen and an excess of CO to consume all of the hydrogen. So the number of moles of hydrogen gas we have is: 2.93 l / 22.4 l/mol = 0.130803571 mol And since it takes 2 moles of hydrogen gas to make 1 mole of methanol, divide by 2, getting. 0.130803571 mol / 2 = 0.065401786 mol Now we just need to multiply the number of moles of methanol by its molar mass. First lookup the atomic weights involved. Atomic weight carbon = 12.0107 g/mol Atomic weight hydrogen = 1.00794 g/mol Atomic weight oxygen = 15.999 g/mol Molar mass CH3OH = 12.0107 + 4 * 1.00794 + 15.999 = 32.04146 g/mol So the mass produced is 32.04146 g/mol * 0.065401786 mol = 2.095568701 g And of course, properly round the answer to 3 significant digits, giving 2.10 grams.</span>
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Analyse the temperature versus time graph of water, given below.
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Explanation:

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Lysine is an amino acid that is an essential part of nutrition but which is not synthesized by the human body. What is the molar
nata0808 [166]

Answer:

The molar mass of lysine using the ideal gas equation for this problem is 146.25 g/mole.

Explanation:

The ideal gas equation PV = nRT, was derived from the ABC laws (Avogadros, Boyles and Charles laws). We need to obtain the value for the number of moles n.

The parameters of this equation are:

P = 1.918 atm

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In the titration of wine to determine the acid concentration, 10.0 mL of wine was placed in a beaker and diluted with 40.0 mL of
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Answer:

0.0042 M is the molarity of tartaric acid in this sample of wine.

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is tartaric acid

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=?\\V_1=10.0+40.0 mL=50.0 mL\\n_2=1\\M_2=0.051 M M\\V_2=8.20 mL

Putting values in above equation, we get:

2\times M_1\times 50.0 mL=1\times 0.051 M\times 8.20 mL

M_1=\frac{1\times 0.051 M\times 8.20 mL}{2\times 50.0 mL}=0.0042 M

0.0042 M is the molarity of tartaric acid in this sample of wine.

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