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Lelu [443]
3 years ago
15

Consider this reaction: 2al(s) + 3 cucl2(aq) → 2alcl3(aq) + 3 cu(s) if the concentration of cucl2 drops from 1.000 m to 0.655 m

in the first 30.0 s of the reaction, what is the average rate of reaction over this time interval?
Chemistry
1 answer:
kirza4 [7]3 years ago
8 0
The average rate of reaction over a given interval can be calculated by taking the difference of concentration on a particular given reactant, and dividing it by the total time. In this case, (1.00 M - 0.655 M)/30 s = 0.0115 M/s, or 0.0115 mol/L-s, and this is the final rate of reaction.
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Explanation:

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So, if we will plot a graph between absrobance and concentration then we will obtain a straight line

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   The slope of graph = \frac{\text{difference in absrobance at two points}}{\text{difference in concentrations at those points}}

The given data is as follows.

     A_{1} = 0.412 (first point)

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Hence, putting these values into the above formula we will calculate the value of slope as follows.

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                     = \frac{0.642 - 0.412}{0.475 - 0.240}

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It is known that for the graph, line equation can be written as follows.

                       y = mx + c  ........... (1)

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Hence, calculate the value of intercept as follows.

           0.412 = 0.24 \times 0.978 + c

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As it is given that the absorbance values 0.454 (the y-axis value). Therefore, putting this value into equation (1) we get the following.

                     y = mx + c

                  0.454 = x \times 0.978 + 0.178

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