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2 years ago

Are there a mole of golf in a 200 g gold necklace

Chemistry

1 answer:

meriva2 years ago

4 0

Explanation:

The answer is 0.5 moles of gold

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Strontium sulfate becomes less soluble in an aqueous solution when sodium sulfator is added because

horsena [70]

Answer:

The addition of sulfate ions shifts equilibrium to the left.

Explanation:

Hello!

In this case, according to the following ionization of strontium sulfate:

$SrSO_3(s)\rightleftharpoons Sr^{2+}+SO_4^{2-}$

It is evidenced that when sodium sulfate is added, sulfate, $SO_4^{2+}$ is actually added in to the solution, which causes the equilibrium to shift leftwards according to the Le Ch athelier's principle. Thus, the answer in this case would be:

The addition of sulfate ions shifts equilibrium to the left.

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2 years ago

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As an electron in an atom moves from a higher energy state to a lower energy state, the atom

Verdich [7]

Answer:B

Explanation:

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2 years ago

What is the vitamin in an apple?

bulgar [2K]

Answer:

98 IU

Vitamin A

Explanation:

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3 years ago

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What is metal and non metal with differenties

Monica [59]

Answer:

i have no clue

Explanation:

i have no clue

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2 years ago

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Arrange the molecules H2O, NH3, Ar, NaCl in order of expected increasing boiling points. 1. None of these 2. NaCl, H2O, NH3, Ar

Aleks04 [339]

Answer:

Option (4) is correct

Explanation:

NaCl is an ionic solid. $Na^{+}$ and $Cl^{-}$ ions are held together by strong coloumbic attractive force. Hence NaCl has highest boiling point'
Ar is a monoatomic molecule. Hence only weak london dispersion force exists between Ar atom/molecules. Hence it requires lowest amount of energy to boil and thereby possess lowest boiling point.
$NH_{3}$ and $H_{2}O$ are polar protic molecules. Hence they possess london dispersion force, dipole-dipole force and hydrogen bonding as intermolecular forces.
Dipole-dipole force is stronger in $H_{2}O$ than $NH_{3}$ due to more polar O-H bond than N-H bond. Also molecular weight of $H_{2}O$ is higher than $NH_{3}$ . So, more energy is required to boil $H_{2}O$ . So, $H_{2}O$ has higher boiling point than $NH_{3}$

Hence order of boiling point : $NaCl>H_{2}O>NH_{3}>Ar$

4 0

2 years ago