C
SO2
5
2
X
5.44
Cross multiply to solve
2x = 27.2
X = 13.6 moles C
Answer:
3.37kg of NaCl is the salt content of the dead sea
Explanation:
A concentration of 33.7% means there are 33.7g of NaCl in 100mL of solution.
To solve this question we need to convert 10.0L to mililiters, and then, solve for the mass of NaCl in grams and convert it to kg:
<em>Volume in milliliters:</em>
10.0L * (1000mL / 1L) = 10000mL
<em>Mass of NaCl:</em>
10000mL * (33.7g NaCl / 100mL) = 3370g NaCl
<em>In kg:</em>
3370g * (1kg / 1000g) =
<h3>3.37kg of NaCl is the salt content of the dead sea</h3>
Answer:
The correct answer is d. 6H20 + 6CO2 the reactant in the chemical reaction 6H2O + 6CO2 ---> C6H12O6 + 6O2 is 6H20 + 6CO2. Remember that the reactant is always at the left side of the equation. So the correct answer is 6H20 + 6CO2 since it's in the left of the equation. I hope this answer helped you.
When hydrogen is attached to a more electronegative element, the more electronegative atom becomes partially negative.
They are all correct good job bud I hope it helps and good luck
