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lakkis [162]
3 years ago
7

How do I do this question?

Physics
2 answers:
iogann1982 [59]3 years ago
6 0
You take 10.0/12.0 and presto answer
iren2701 [21]3 years ago
3 0
You take 10.0/12.0 and you will get your answer
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Use your data to predict what a 400g bag would weigh.
Kobotan [32]

3.92N

Explanation:

Given mass:

Mass of bag = 400g

The mass of a substance is the amount of matter it contains.

Weight of a substance is the vertical force acting on a body in the presence of gravity.

  Weight = mass x gravity

Since the mass of the bag is 400g;

 Now we convert to kg

   1000g  = 1kg

   400g = \frac{400}{1000}  =  0.4kg

  Weight of bag = 0.4kg x 9.8m/s²

   Weight of bag = 3.92N

learn more:

Weight and mass brainly.com/question/5956881

#learnwithBrainly

6 0
3 years ago
A truck starts from rest with an acceleration of 0.3 m/ S^2 find its speed in km/h when it has moves through 150 m​
Nadya [2.5K]

Answer:

9.5 m/s

Explanation:

Distance, S = 150m

Acceleration, a = 0.3 m/s^2

Initial velocity, u = 0 m/s

Final velocity, v

Use kinematics equation

v^2 - u^2 = 2aS

v^2 - 0 = 2*0.3*150 = 90

v = sqrt(90) = 9.49 m/s

3 0
3 years ago
Read 2 more answers
The electric field in a region of space increases from 0 to 2150 N/C in 5.00 s. What is the magnitude of the induced magnetic fi
Feliz [49]

To solve this problem we will use the Ampere-Maxwell law, which   describes the magnetic fields that result from a transmitter wire or loop in electromagnetic surveys. According to Ampere-Maxwell law:

\oint \vec{B}\vec{dl} = \mu_0 \epsilon_0 \frac{d\Phi_E}{dt}

Where,

B= Magnetic Field

l = length

\mu_0 = Vacuum permeability

\epsilon_0 = Vacuum permittivity

Since the change in length (dl) by which the magnetic field moves is equivalent to the perimeter of the circumference and that the electric flow is the rate of change of the electric field by the area, we have to

B(2\pi r) = \mu_0 \epsilon_0 \frac{d(EA)}{dt}

Recall that the speed of light is equivalent to

c^2 = \frac{1}{\mu_0 \epsilon_0}

Then replacing,

B(2\pi r) = \frac{1}{C^2} (\pi r^2) \frac{d(E)}{dt}

B = \frac{r}{2C^2} \frac{dE}{dt}

Our values are given as

dE = 2150N/C

dt = 5s

C = 3*10^8m/s

D = 0.440m \rightarrow r = 0.220m

Replacing we have,

B = \frac{r}{2C^2} \frac{dE}{dt}

B = \frac{0.220}{2(3*10^8)^2} \frac{2150}{5}

B =5.25*10^{-16}T

Therefore the magnetic field around this circular area is B =5.25*10^{-16}T

3 0
3 years ago
NEED HELP NOW
zaharov [31]
<span>Z is present outside the solar system.</span>
7 0
4 years ago
Read 2 more answers
A 23.5 kg object travels a distance of 85 m in 30 s. Find the momentum. (Hint: you must find speed first)
kherson [118]
Speed = 85/30 m/s
Momentum = 23.5 * 85/30 = ....
4 0
4 years ago
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