describe how acceleration and velocity are related and specify if these are scalar and vector quantities

Physics

1 answer:

vitfil [10]3 years ago

8 0

Velocity is the rate of change in distance over change in time, this can be written as:

v = Δd / Δt

While acceleration is the rate of change in velocity over change in time, this is written as:

a = Δv / Δt

<span>Both quantities are vector quantities because negative values means that the acceleration or velocity is acting on the opposite direction.</span>

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The slow coning pattern of the spin axis of the Earth's precession will move the end of this axis in a complete circle in a peri

GREYUIT [131]

Answer:

26000 years

Explanation:

Precession describes the angular motion of the Earth's body. Since the attitude of telescopes relative to the Earth's body can be controlled with high accuracy, and telescopes can measure the direction of incoming light also with high accuracy, the motion of Earth is under permanent high precision monitoring. Thus the basic numerical descriptor of precission, an angular rate of 5029.0966 seconds of arc per Julian century, traditionally denoted p (for precession) is a measured value from observed coordinate changes of thousands of stars over, say, two centuries. The understanding of this value in terms of forces acting on an oblate Earth from the Moon is well understood so that an extrapolation back and forth over a few full cycles contains little uncertainties. Of course, you can find details on the coordinate transformations mentioned above (the direct observational effect of precession) on the net. I was surprised to see that the Wikipedia article on precession covers the astronomical aspect very poorly. You thus better look for other sources.

3 0

4 years ago

How much work does this force do as the particle moves along the x-axis from x = 0 to x = l? express your answer in terms of the

nydimaria [60]

<h3><u>Answer</u>;</h3>

= F0 L ( 1 - 1/e )

<h3><u>Explanation;</u></h3>

Work done is given as the product of force and distance.

In this case;

Work done = ∫︎ F(x) dx

= F0 ∫︎ e^(-x/L) dx

= F0 [ -L e^(-x/L) ] between 0 and L