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Brrunno [24]
3 years ago
8

With manual transmission, use your right foot for the brake and accelerator and left foot for the clutch true or false

Physics
2 answers:
jeka943 years ago
6 0

yes the statement "With manual transmission, use your right foot for the brake and accelerator and left foot for the clutch"  is true .

in manual transmission , we have clutch , brake and acceleration in sequence. the clutch on leftmost side and used while changing the gear. in the middle we have brakes used to slow down the vehicle. and on the rightmost , we have accelerator to speed up the vehicle or to maintain the speed.  in right hand drive , the left leg is used for clutch  and right leg is used to operate both accelerator and brake one at a time,

GaryK [48]3 years ago
4 0

This is true!

Hope this helps!

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ok so for 99 points(not multiple choice)what is one way to separate salt from grains NO MULTIPLE CHOICE
iragen [17]
Place mixtuer into water. stir mixture into water, wait untill salt is disoldved. Strain out grain. boil water intill only salt is left. Hope this helps! ^-^
6 0
3 years ago
Read 2 more answers
Please help!!!! Will mark brainliest.
julia-pushkina [17]

Answer:

Approximately 8.4 \times 10^{2}\; \rm N, assuming that g = 9.8\; \rm m \cdot s^{-2}.

Explanation:

Let m and a denote the mass and acceleration of Spiderman, respectively.

There are two forces on Spiderman:

  • Downward gravitational attraction from the earth: W = m \cdot g.
  • Upward tension force from the strand of web F(\text{tension}).

The directions of these two forces are exactly opposite of one another. Besides, because Spiderman is accelerating upwards, the magnitude of F(\text{tension}) (which points upwards) should be greater than that of W (which points downwards towards the ground.)

Subtract the smaller force from the larger one to find the net force on Spiderman:

(\text{Net Force}) = F(\text{tension}) - W.

On the other hand, apply Newton's Second Law of motion to find the value of the net force on Spiderman:

(\text{Net Force}) = m \cdot a.

Combine these two equations to get:

m \cdot a = (\text{Net Force}) = F(\text{tension}) - W.

Therefore:

\begin{aligned}& F(\text{tension})\\ &= m \cdot a + W \\ &= m \cdot (a + g)\\ &= 76\; \rm kg \times \left(1.3\; \rm m \cdot s^{-2} + 9.8\; \rm m \cdot s^{-2}\right)\\ &\approx 8.4\times 10^{2}\; \rm N\end{aligned}.

By Newton's Third Law of motion, Spiderman would exert a force of the same size on the strand of web. Hence, the size of the force in the strand of the web should be approximately 8.4\times 10^{2}\; \rm N (downwards.)

4 0
3 years ago
What is the acceleration of a racing car if it's speed is increased uniformly from 44 m /s to 66 m / s over an 11 second period
jolli1 [7]

Answer:

the acceleration of the race car is 2 m/s²

Explanation:

Given;

initial velocity of the race car, u = 44 m/s

final velocity of the race car, v = 66 m/s

time of motion of the race car, t = 11 s

The acceleration of the race car is  calculated as;

a = \frac{v-u}{t} \\\\a = \frac{66-44}{11} \\\\a = 2 \ m/s^2

Therefore, the acceleration of the race car is 2 m/s²

7 0
2 years ago
What is the average speed of a train that travels at 100km/hr for 6 hours and then 120km/hr for 5 hours
Sindrei [870]

Answer:

Explanation:

Average speed = Total distance / Total time.

100 km/hr

r = 100 km / hr

t = 6 hours

d = 6 * 100 = 600 km

120 km / hr

r = 120 km / hr

t = 5 hour

d = 120 * 5

d = 600 km

Total distance = 600 + 600 = 1200 km

Total time = 5 hour + 6 hours = 11 hours.

Average speed = 1200 km / 11 hours = 109.1

5 0
3 years ago
Is the classification for an instrument that produces sound whne a string or strings stretched between two points is plucked?
Yuki888 [10]
The correct answer for the question is Chordophone 
Chordophone is an instrument in which a stretched, vibrating string produces the initial sound. Strings instruments produce sound through the vibration of strings. The length, tightedness, and thickness determines the sound produced by the strings. 
5 0
3 years ago
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