All categories

3 years ago

With manual transmission, use your right foot for the brake and accelerator and left foot for the clutch true or false

2 answers:

jeka943 years ago

6 0

yes the statement "With manual transmission, use your right foot for the brake and accelerator and left foot for the clutch" is true .

in manual transmission , we have clutch , brake and acceleration in sequence. the clutch on leftmost side and used while changing the gear. in the middle we have brakes used to slow down the vehicle. and on the rightmost , we have accelerator to speed up the vehicle or to maintain the speed. in right hand drive , the left leg is used for clutch and right leg is used to operate both accelerator and brake one at a time,

GaryK [48]3 years ago

4 0

This is true!

Hope this helps!

You might be interested in

An object is placed 10 cm in front of a diverging mirror. What is the focal length of the mirror if the image appears 2 cm behin

Dafna1 [17]

Answer:

the focal length of the mirror is : $f=-2.5\,\,cm$

Explanation:

Use the formula for the formation of image using a divergent mirror and recalling that the image (s') that this mirror formed is virtual, so it is entered as a negative number in the formula. Use the object position (s) as 10, the image position (s') as -2, and derive the value of the focal length:

$\frac{1}{s} +\frac{1}{s'}=\frac{1}{f}\\\frac{1}{10} +\frac{1}{-2}=\frac{1}{f}\\\frac{1}{10} -\frac{1}{2}=\frac{1}{f}\\\frac{10\,f}{10} -\frac{10\,f}{2}=\frac{10\,f}{f}\\f-5\,f=10\\-4\,f=10\\f=-2.5\,\,cm$

6 0

3 years ago

Problem 9: Suppose you wanted to charge an initially uncharged 85 pF capacitor through a 75 MΩ resistor to 90.0% of its final vo

Bingel [31]

Answer:

$t=14.678\times 10^{-3}s$

Explanation:

Given:

Capacitance, C = 85 pF = 85 × 10⁻¹² F

Resistance, R = 75 MΩ = 75×10⁶Ω

Charge in capacitor at any time 't' is given as:

$Q=Q_o(1-e^{-\frac{t}{RC}})$

where,

Q₀ = Maximum charge = CE

E = Initial voltage

t = time

also, Q = CV

V= Final voltage = 90% of E = 0.9E

thus, we have

$C\times 0.9E=CE(1-e^{-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}})$

$0.9=1-e^{-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}}$

$e^{-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}}=1-0.9=0.1$

taking log both sides, we get

$ln(e^{-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}})=ln(0.1)=ln(\frac{1}{10})$

$-\frac{t}{75\times 10^6\ \times\ 85\times 10^{-12}}=-ln(10)$

$t=75\times 10^6\ \times\ 85\times 10^{-12}\times ln{10}$

$t=14.678\times 10^{-3}s$

3 0

3 years ago

Tragically, the united states lost astronauts in accidents involvin

sweet-ann [11.9K]

The quest to put Americans on the moon before the Soviets do. During the Space Race, a couple of astronauts went up into space only to be tragically killed in an explosion.

7 0

3 years ago

Read 2 more answers

Anybody wanna play among us?

kherson [118]

Answer:

yess

Explanation:

8 0

3 years ago

Read 2 more answers

HELPPP PLEASEEE!!!!!

devlian [24]

Answer:

1) The speed of sound increases

2) 440 Hz

3) 29°C

4) 17°C

5) 434 Hz

6) 12 m/s

7) 17.3 m

Explanation:

1) The speed of sound increases

2) V = f×λ

f = V/λ = 343/0.78 = 439.744 ≈ 440 Hz

3) V = f×λ

512 × 0.68 = 348.16 m/s

348.16 - 331 = 17.16

T = 17.16/0.6 = 28.6 ≈ 29°C

4) Increase in speed = 350 - 340 = 10

Increase in temperature = 10/0.6 = 16.67° ≈ 17°C

5) f = V/λ = 343/0.79 = 434 Hz

6) 331 + 0.6×30 - (331 × 0.6 ×10) = 12 m/s

7) V = 331 + 0.6×25 = 346m/s

λ = 346/20 = 17.3 m

5 0

3 years ago