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Lerok [7]
3 years ago
5

suppose a car of 1200kg is moving with a velocity of 40km/hr therefore its kinetic energy is not zero. 1. explain briefly what h

appens to its kinetic energy when the driver applies the breaks and the car stops​
Physics
2 answers:
mezya [45]3 years ago
8 0

Answer:

Explanation:

For starters begin with a warning not to touch the brake drums. All of the KE is transferred to the brake drums. The result is a large rise in temperature. Heat. If you press hard on the brakes, rubber is left on the road and there is heat involved in that too.

frutty [35]3 years ago
4 0

Answer:

KInetic energy reduces.

Explanation:

Application of breaks reduces velocity. Reduction of velocity constitutes velocity reduction.

For more help contact +1 (304) 223-3136

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Car A of mass 1200kg traveling at 10m/s , collided in too the back of the car B, which is stationary. Following the collision,.
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Car B has a mass of 800 kg.

General Formulas and Concepts:

<u>Momentum</u>

Law of Conservation of Momentum: \displaystyle m_1v_{1i} + m_2v_{2i} = (m_1 + m_2)v_{f}

Explanation:

<u>Step 1: Define</u>

<em>Identify variables</em>

[Given] m₁ = 1200 kg

[Given] v₁i = 10 m/s

[Solve] m₂

[Given] v₂i = 0 m/s

[Given] vf = 6 m/s

<u>Step 2: Solve for m₂</u>

  1. Substitute in variables [Law of Conservation of Momentum]:                       (1200 kg)(10 m/s) + m₂(0 m/s) = (1200 kg + m₂)(6 m/s)
  2. Multiply:                                                                                                             12000 kg · m/s = (1200 kg + m₂)(6 m/s)
  3. Isolate m₂ term:                                                                                                2000 kg = 1200 kg + m₂
  4. Isolate m₂:                                                                                                         800 kg = m₂
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