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4 years ago

Solve 50q-43=52q-81

2 answers:

8 0

Move the variables to one side and the constants to the other

50q - 43 = 52q - 81

50q (-52q) - 43 (+43) = 52q (-52q) - 81 (+43)

50q - 52q = -81 + 43

-2q = -38

isolate the q, divide -2 from both sides

-2q/-2 = -38/-2

q = -38/-2

q = 19

hope this helps

mestny [16]4 years ago

6 0

The answer is 19
50q-43=52q-81 Subtract 50q from both sides
-43=2q-81 Add 81 to both sides
38=2q Divide by 2 on both sides
19=q

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Find the value of p for which the given pair of linear equations have infinitely many solutions for 4X + 3 Y - 4 is equals to ze

tino4ka555 [31]

Answer:

x=8/3

y= -20/9

Step-by-step explanation:

4X + 3Y -4 =0

Linear egquations must in

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4 years ago

7.6375 correct to 2 decimal place

Reil [10]

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4 years ago

Find the value of x so that the function has the given value. <br> q(x)=12x−3; q(x)=−4

Anna [14]

Answer:

$- \frac{1}{ 12}$

Step-by-step explanation:

since q(x)=-4

substitute

hence

-4=12x-3

take -3 to the other side where it becomes positive

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3 years ago

A bag contains 6 red balls numbered 1, 2, 4, 5, 8, 9 and 4 white balls numbered 3, 6, 7, 10,

geniusboy [140]

Answer:

60%

a. 80%

b. 70%

Step-by-step explanation:

In this case we are first asked for the probability that when drawing a ball at random it is 8, 9 and 4 white balls numbered 3, 6, 7, 10, that is 6 balls. We know that there are a total of 10 balls since they are 6 red and 4 white, 6 + 4 = 10.

Therefore the probability is:

6/10 = 0.6

that is to say that the probability that it is one of these balls is 60%

to. that is red or odd,

red are 1, 2, 4, 5, 8, 9 and in addition to that, in white there is one with 3 and with 7 that are odd, making them 8 balls, therefore:

8/10 = 0.8

In other words, the probability is 80%

b. white or even,

the white ones are 3, 6, 7, 10 and in the red ones the 2, 4 and 8 are even, that is to say that they are 7 balls, which means that:

the probability is:

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3 years ago

If a car is 13.5 feet long and there are 3 feet between each car, how many cars can be on a mile section of the highway?

Vikentia [17]

1 mile = 5,280 feet

Car + space = 13.5 + 3 = 16.5 feet

5,280 / 16.5 = 320

Answer: 320 cars

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3 years ago