6) What is located in the nucleus?

Use the Gizmo to mix 200 g of copper at 100 °C with 1,000 g of water at 20 °C. Record the data and calculated answers for copper

xxTIMURxx [149]

Answer:

Explanation:Use the Gizmo to mix 200 g of copper at 100 °C with 1,000 g of water at 20 °C. Record the data and calculated answers for copper in the 2 tables below. Accepted values for % error calculations can be found below these 2 tables.

DATA

Copper

Lead

Mass of Metal

3 0

3 years ago

The eu(iii) standards added to the groundwater sample contained 0.168 ng/ml (ppb) of eu(iii). calculate the concentration of eu(

Andre45 [30]

The standard addition equation is as followsI_(S+X) (V/V_O )=I_X+I_X/[X]_i [S]_4 (V_S/V_0 ) Here, [X]_i is the initial concentration of analyte, [S]_i is the initial concentration of standard, I_X is signal for analyte, I_(S+X) is signal for standard and analyte, V_0 is the initial volume, V_S is the added standard volume, and V is the total volume.Added volume of standard V_S is-23.3 mL. Initial volume of the sample V_0 is 10.00 mL. Initial concentration of standard ([S]_i) is 0.156 ng/mL.[X]_i= -[S]_i (V_S/V_0 )〖[X]〗_(i )= -(0.156 ng/mL)((-23.3 mL)/(10.00 mL))=0.363 ng/mL
Concentration of U(III) in ground sample is 0.363 ng/mL

6 0

3 years ago

The rate constant of a first order reaction is 0.035 sec-1. How much of a 1.5 M sample of reactant would remain after 28 seconds

andrey2020 [161]

Answer:

0.56 M

Explanation:

Step 1: Given data

Rate constant (k): 0.035 s⁻¹

Initial concentration of the reactant ([A]₀): 1.5 M

Time elapsed (t): 28 s

Step 2: Calculate the amount of reactant ([A]) after 28 seconds

For a first-order kinetics, we will use the following expression.

ln [A] = ln [A]₀ - k × t

ln [A] = ln 1.5 - 0.035 s⁻¹ × 28 s

[A] = 0.56 M

4 0

3 years ago

1. When an acid reacts with a base, what compounds are formed? (1 point) a salt only water only metal oxides only a salt and wat

scoundrel [369]

Answer: 1) only a salt and water

An acid and base reacts together to undergo neutralization to form salt and water.

$HCl+NaOH\rightarrow NaCl+H_2O$

where HCl is an acid and NaOH is a base to form salt (NaCl) and water $(H_2O)$ .

Answer: 2) The formula of the hydrogen ion is often written as $H^+$ .

All acids dissociate in water to give $H^+$ ions.

Answer: 3) Arrhenius acids are substances that ionizes to yield protons in aqueous solution.

$HCl\rightarrow H^++Cl^-$

Arrhenius bases are substance that ionizes to yield hydroxide ions in aqueous solution.

$NaOH\rightarrow Na^++OH^-$

Answer: 4) A conjugate acid base pair transfers hydrogen ion.

$CH_3COO^-+H_2O\rightarrow CH_3COOH+H_3O^+$

Here $CH_3COO^-$ accepts a proton and thus act as a base and the corresponding $CH_3COOH$ is its conjugate acid.

Answer: 5) Bronsted Lowry acid is a substance that donates protons. Bronsted Lowry base is a substance that accepts protons.

$NH_4^+$ and $NH_3$

$NH_3+H^+\rightarrow NH_4^+$

$NH_3$ is a acid which accepts proton and thus acts as base to form conjugate acid $NH_4^+$ .

4 0

3 years ago

Read 2 more answers

If an ice cube melts at 0ºC but water also freezes at 0ºC, what is the difference between melting and freezing in terms of…….

devlian [24]

Answer:

8. When melting the energy of the ice cubes increases and when frezzing the energy of the water decreases.

9. When melting the otion of the particles speed up, when freezing the motion of the particles slow down.

Explanation:

8. The energy involved in the phase changes

When an ice cube melts at 0ºC it must absorb or gain energy from the surroundings. This is an endothermic process, because the energy of the liquid water shall be higher than the energy of the starting ice cubes.

In conclusion, when melting the energy of the water increases.

On the other hand, when the liquid water freezes, also at 0ºC, the flow of heat energy is from the liquid water to the surroundings. This is an exothermic process because the water releases heat. At the end, the energy of the frozen water will be lower than the energy of the liquid water.

In conclusion, when freezing the enery of the water decreases.

9. The motion of the particles of the substances during the phase changes

The particles of liquid substances are in constant motion, which is what allows them to flow. This is because the particles (molecules or atoms) are relatively distant from each other, with relatively low intermolecular forces. Thus, they can slide on each other.

On the other hand, the solid substances have the particles in fixed position in structures called crystals. The particles vibrate but do not translation motion.

In conclusion, the difference is that the motion of the particles during melting increases and the motion of th particles during freezing decreases.

4 0

3 years ago