Question

What is the initial temperature (°C) of a system that has the pressure decreased by 10 times while the volume increased by 5 times with a final temperature of 150 K?

Answer 1

Answer:

300K

Explanation:

Given pressure of the system decreased by 10 times which means $P_{2} =\frac{P_{1} }{10}$

Given the volume of the system increased by 5 times which means $V_{2} =5\times V_{1}$

Given final temperature $T_{2}=150K$

Let the initial temperature be $T_{1}$

We know that PV=nRT

As n and R are constant $\frac{PV}{T}=constant$

$\frac{P_{1}V_{1} }{T_{1}} =\frac{P_{2}V_{2}}{T_{2}}$

$T_{1} =\frac{P_1V_1}{P_2V_2} T_{2}$

$T_{1} =2\times T_{2}$

T1=300K