<span>When pKas of polyprotic intermediates have a difference of 2 or more you just average them using the equation: pH = (pKa2 + pKa3) / 2 </span>
<span>pKa2 = -log(Ka2) ; pKa3 = -log(Ka3) </span>
<span>so, for this problem, REGARDLESS OF THE CONCENTRATION GIVEN, the answer is: </span>
<span>pH = (7.2076+12.3767) / 2 </span>
<span>pH = 9.79</span>
D I just took this and got it right
B.) Gravitational force decreases.
You were right !!
The above question is incomplete, here is the complete question:
Calculate the standard molar enthalpy of formation of NO(g) from the following data at 298 K:


Answer:
The standard molar enthalpy of formation of NO is 90.25 kJ/mol.
Explanation:


To calculate the standard molar enthalpy of formation
...[3]
Using Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.
[1] - [2] = [3]


![\Delta H^o_{3}=66.4 kJ - [ -114.1 kJ] = 180.5 kJ](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7B3%7D%3D66.4%20kJ%20-%20%5B%20-114.1%20kJ%5D%20%3D%20180.5%20kJ)
According to reaction [3], 1 mole of nitrogen gas and 1 mole of oxygen gas gives 2 mole of nitrogen monoxide, So, the standard molar enthalpy of formation of 1 mole of NO gas :
=

Answer:
A. All sites B. A site C. E site D. P site
Explanation:
A. Because all sites consequently take place while peptide is synthesized.
B. A site (aminoacyl site) is called so because it binds to charged aminoacyl peptide.
C. Because it is the exit site and it takes the final stage on the uncharged molecule.
D. The P site (peptidil site which takes main role in peptide synthesis.