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soldier1979 [14.2K]
3 years ago
8

Just answer this I guess bc I have more for you guys and girls

Mathematics
1 answer:
Lana71 [14]3 years ago
7 0

Answer:

The answer is 13/15 gallons.

Step-by-step explanation:

2/3 + 1/5

10/15 + 3/15 = 13/15




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What is the greatest perimeter of a rectangle with an area of 39 ft.²
Ulleksa [173]
<span>The area is 39*1=39, and the perimeter would be 39+39+1+1=80. !</span>
3 0
3 years ago
Mathew is watching a car race on TV. His favorite car covered 10 laps of 3.6 miles each in 18 minutes.What is average speed of t
Mariana [72]
Great job! You’re correct
5 0
3 years ago
kerry and four friends want to the movies they purchased sodas costing $5.50 each and hotdog each cosing $12.75 they each contri
grandymaker [24]

Answer:

they will each receive $1.75

Step-by-step explanation:

5.50*5= 27.50

12.75*5= 63.75

27.50+63.75= 91.25

20*5= 100

100-91.25=8.75

8.75/5= $1.75

hope this helps

4 0
3 years ago
A rectangle is 6yards longer than it is wide. Find the dimensions of the rectangle if it’s area is 187 square yards
emmasim [6.3K]

Answer:

Width = 11 yards

Length = 17 yards

Step-by-step explanation:

First of all, the length of the rectangle is 6 yards longer than the width, this means, length = width + 6 yards. This dimensions can be represented on figure 1, where <em>w</em> is width, and <em>l</em>, for length.

We know the area of a rectangle is A = width x length

For our case 187 = w . (w + 6)

Using the Distributive Property for the multiplication we obtain

187 = w^{2} +6w

w^{2} +6w-187 =0,

Using the quadratic formula w=\frac{-b\±\sqrt{b^{2}-4ac } }{2a} where a = 1, b = 6, c = - 187 and replacing into the formula, we will have:

w=\frac{-6\±\sqrt{6^2-4(1)(-187)} }{2(1)}

w=\frac{-6\±\sqrt{36+748} }{2}=\frac{-6\±\sqrt{784} }{2}=\frac{-6\±28}{2}

We have two options: w=\frac{-6+28}{2}=\frac{22}{2}=11  yards

Or

w=\frac{-6-28}{2}=\frac{-34}{2}=-17 yards But a distance (width) can not be negative so, this answer for w must be discarded.

The answer must be width = 11 yards.

To find the length l =\frac{187}{11}=17 yards

6 0
3 years ago
The temperature at 6:00 P.M. was 3°C. At midnight, the temperature was -2°C.
aliina [53]

Answer:

-5 degrees

Step-by-step explanation:

In this scenario, since the final temperature was the temperature that existed at midnight then that value is subtracted from the initial temperature which was at 6:00 PM. Therefore we do the following calculation...

(-2) - 3 = x

-5 = x

Finally, we can see that there was a change in temperature of -5 degrees between 6:00 P.M. and Midnight. Meaning that the temperature during this time dropped a total of 5 degrees. Since, real numbers include negatives then the answer to this question is -5 degrees

5 0
3 years ago
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