Answer:
7boxes
Step-by-step explanation:
A box can hold a maximum of 8 cans
You have a total of 50 cans
The problem here is to determine the minimum number of boxes that can hold the 50 cans
Let the minimum number of boxes = y
The minimum required will be such that:
The Product of The number of cans X Number of Required boxes ≥50
8y≥50
y≥50/8
y≥6.25
Since a box have a fractional value, the minimum number of boxes required to store 50 cans will be the nearest whole number which in this case is 7.