3 years ago

Which numbers belong to the solution set of the inequality? check all that apply. x+10<50

Mathematics

1 answer:

Lelechka [254]3 years ago

4 0

THE CORRECT SOLUTION WOULD BE THE LISTED LETTERS. B. , F.

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(6+8)^2=6^2+8^2 statement true

ddd [48]

this is false

(6+8)^2= 196

6^2+8^2=100

They are not equal so this is a false statement

5 0

3 years ago

PLEASE HELP ASAP WILL GIVE BLAINLY PTS

ddd [48]

Answer:

$\large\boxed{C.\ \dfrac{2x-20}{x^2+6x-40}}$

Step-by-step explanation:

$f(x)=\dfrac{x-16}{x^2+6x-40}=\dfrac{x-16}{x+10x-4x-40}=\dfrac{x-16}{x(x+10)-4(x+10)}\\\\f(x)=\dfrac{x-16}{(x-4)(x+10)}\\\\g(x)=\dfrac{1}{x+10}\\\\f(x)+g(x)=\dfrac{x-16}{(x-4)(x+10)}+\dfrac{1}{x+10}=\dfrac{x-16}{(x-4)(x+10)}+\dfrac{1(x-4)}{(x-4)(x+10)}\\\\=\dfrac{x-16+x-4}{(x-4)(x+10)}=\dfrac{2x-20}{(x-4)(x+10)}=\dfrac{2x-20}{x^2+6x-40}$