First, we need to add up all the percentages to make sure we have 100%.
25.5% + 0.03% = 25.53%
This means that 74.47% of the students chose something other than basketball or soccer.
The amount of students you stated there were was 2553.
25.5% of 2553 is 651 students and
0.03% is 8 students.
Now, we divide 651 by 8 to determine the amount of times over basketball was chosen.
651 ÷ 8 = 81
Basketball was chosen 81 times over again compared to soccer.
To find how much more times basketball was chosen, subtract 8 from 651
651 - 8 = 643
Basketball was chosen 643 times more than soccer.
The height of the fence is irrelevant. The bottom of the ladder is 3+8 = 11 feet from the building. The window is 14ft above the ground:
sqrt(14^2+11^2) = length of your ladder.
Answer:
12
Step-by-step explanation:
add 3x both sides
8x +3 = 99
subtract 3 on both sides
8x = 96
divide by 8
x = 96/8 = 12
First, find the radius of the circle. The radius of a circle is half the diameter. r=13/2=6.5
Second, use the equation A=pi * r^2 to find the area of the circle.
A=(3.14) * (6.5^2) = 132.665m^2
so the answer is 132.7 m^2.
Answer:
<h2><DEF = 40</h2><h2><EBF = <EDF = 56</h2><h2><DCF = <DEF =40</h2><h2><CAB = 84</h2>
Step-by-step explanation:
In triangle DEF, we have:
<u>Given</u>:
<EDF=56
<EFD=84
So, <DEF =180 - 56 - 84 =40 (sum of triangle angles is 180)
____________
DE is a midsegment of triangle ACB
( since CD=DA(given)=>D is midpoint of [CD]
and BE = EA => E midpoint of [BA] )
According to midsegment Theorem,
(DE) // (CB) "//"means parallel
and DE = CB/2 = FB =CF
___________
DEBF is a parm /parallelogram.
<u>Proof</u>: (DE) // (FB) ( (DE) // (CB))
AND DE = FB
Then, <EBF = <EDF = 56
___________
DEFC is parm.
<u>Proof</u>: (DE) // (CF) ((DE) // (CB))
And DE = CF
Therefore, <DCF = <DEF =40
___________
In triangle ACB, we have:
<CAB =180 - <ACB - <ABC =180 - 40 - 56 =84(sum of triangle angles is 180)
