The gravitational force exerted on a baseball is 2.21 N down. A pitcher throws the ball horizontally with velocity 18.0 m/s by u
niformly accelerating it along a straight horizontal line for a time interval of 170 ms. The ball starts from rest. a).- Through what distance does it move before its release? b).- what are the magnitude and direction of the force the pitcher exerts an the ball?.
1 answer:
Answer:
(a) S = 1.8m
(b) F = 23.9N
Explanation:
The solution to this problem requires the knowledge of the concepts of constant acceleration motion for part (a) and newton's second law for part(b).
(a) s =(u + v)/2 ×t
(b) F = m(v-u)/t
u = 0m/s because the pitcher starts to throw the ball from rest
See attachment below for full solution steps.
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Explanation:
Formula to determine the critical crack is as follows.
= 1,
= 24.1
[/tex]\sigma_{y}[/tex] = 570
and,
= 427.5
Hence, we will calculate the critical crack length as follows.
a =
=
=
Therefore, largest size is as follows.
Largest size = 2a
=
=
Thus, we can conclude that the critical crack length for a through crack contained within the given plate is .