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3 years ago

PLS HELP.

Physics

1 answer:

luda_lava [24]3 years ago

8 0

Answer:

F = 120 N

Explanation:

If we ASSUME that the circle is horizontal

Fc = mv²/R = 0.309(12.9²)/0.429 = 119.8617... N

There would also be the vertical force of weight

Fg = mg = 0.309(9.81) = 3.03129 N

which is small enough to ignore, but we can check

F = √(3.03129² + 119.8617² = 119.9000... N

Yup, ignorable.

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If a force always acts perpendicular to an object's direction of motion, that force cannot change the object's kinetic energy.

laiz [17]

This is very good conceptual question and can clear your doubts regarding work-energy theorem.
Whenever force is perpendicular to the direction of the motion, work done by that force is zero.
According to work-energy theorem,
Work done by all the force = change in kinetic energy.

here, work done = 0.
Therefore,
0=change in kinetic energy
This means kinetic energy remains constant.
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3 years ago

PLS ANSWER ASAP

poizon [28]

Answer:

Gravity, normal force, friction, and air resistance.

Explanation:

Assuming the ball is on earth, there is always gravity acted upon the object.

Since the problem said that the golf ball is moving throughout the air, we can tell that there will be air resistance and friction(air resistance is a type of friction). There is also normal force pushing on the ball as it bumps into the air, as the air is pushing back with an equal and opposite force.

I don't know what you mean by "applied", so I don't think there's that type of force exerted on the ball.

Lastly, tension only occurs when you pull a string/rope. There is no string/rope in this case, so there is no tension exerted on the ball.

I hope this helped you.

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3 years ago

Two carts, one of mass 2m and one of mass m, approach each other with the same speed, v. When the carts collide, they hook toget

Nikitich [7]

Answer:

<em>Second option</em>

Explanation:

<u>Linear Momentum</u>

The linear momentum of an object of mass m and speed v is

P=mv

If two or more objects are interacting in the same axis, the total momentum is

$P_t=m_1v_1+m_2v_2+...$

Where the speeds must be signed according to a fixed reference

The images show a cart of mass 2m moves to the left with speed v since our reference is positive to the right

$P_1=-2mv$

The second cart of mass m goes to the right at a speed v

$P_2=mv$

The total momentum before the impact is

$P_t=-2mv+mv=-mv$

The total momentum after the collision is negative, both carts will join and go to the left side

The first option shows both carts with the same momentum before the collision and therefore, zero momentum after. It's not correct as we have already proven

The third option shows the 2m cart has a positive greater momentum than the other one. We have proven the 2m car has negative momentum. This option is not correct either

The fourth option shows the two carts keep separated after the collision, which contradicts the condition of the question regarding "they hook together".

The second option is the correct one because the mass $m_2$ has a negative momentum and then the sum of both masses keeps being negative

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4 years ago

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