The new equation after shifting will be:
Step-by-step explanation:
Function trnafomations upward and left are defined as:
Upward:
f(x) => f(x)+b where b is an integer
Left:
f(x) => f(x+b) where b is an integers
Given function is:
Shifting the function 5 units left
Shifting the function upward 2 units
So,
The new equation after shifting will be:
Keywords: Functions, shifting
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The square root of a a negative integer is imaginary.
It would still be a negative under a square root if you multiplied it by 2, therefor it will still be imaginary, or I’m assuming as your book calls it, undefined.
2•(sqrt-1) = 2sqrt-1
If you add a number to -1 itself, specifically 1 or greater it will become a positive number or 0 assuming you just add 1. In that case it would be defined.
-1 + 1 = 0
-1 + 2 = 1
If you add a number to the entire thing “sqrt-1” it will not be defined.
(sqrt-1) + 1 = 1+ (sqrt-1)
If you subtract a number it will still have a negative under a square root, meaning it would be undefined.
(sqrt-1) + 1 = 1 + (sqrt-1)
however if you subtract a negative number from -1 itself, you end up getting a positive number or zero. (Subtracting a negative number is adding because the negative signs cancel out).
-1 - -1 = 0
-1 - -2 = 1
If you squared it you would get -1, which is defined
sqrt-1 • sqrt-1 = -1
and if you cubed it, you would get a negative under a square root again, therefor it would be undefined.
sqrt-1 • sqrt-1 • sqrt-1 = -1 • sqrt-1 = -1(sqrt-1)
Sorry if this answer is confusing, I don’t have a scientific keyboard, I’ll get one soon.
Hi! :)
It sounds like you need to multiply this fraction.
*16=6
So, Marge used 6 total inches of tape.
Hope this helps!
Answer:
y=4x+7
Step-by-step explanation:
it's in the picture
please mark as brainliest
Answer:
Step-by-step explanation:
f(x) = (x - 1)/(x - 3) < 0
The critical points are x = 1 and x = 3
When x < 1, f(x) > 0
When 1 < x < 3, f(x) < 0
When x > 3, f(x) > 0
Note when x = 3 f(x) has no value and when x = 1 f(x) = 0.
I can't see all the graphs very well but there should be a red line between 1 and 3 with a clear circle on x = 1 and x = 3.
Looks like its the last choice.
