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Vsevolod [243]
3 years ago
8

Module 03: Project Option 1

Mathematics
1 answer:
prisoha [69]3 years ago
8 0
For #1, I have attached the number line.

For #2, I have provided two examples. One shows a different any quality symbol, and the other one shows the same based on absolute values.

For #3, you can see using the number line that -0.5 is the closest to zero.

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What power of 2 is equal to the expression below
Brut [27]

Answer:

Daddy

Step-by-step explanation:

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3 years ago
Which is the graph inequality x-2y_>-12
Zigmanuir [339]

Answer:

The graph for x-2y>=-12 needs to get y aloneso add 2y to both sides to getx >=-12 +2ythen add 12 to both sides of the in equalityx+12 >=2ynext divide each term by 2x/2 + 6 >= yy<= x/2 + 6so the graph connects (0,6) and (2,7) and shade below the solid line

5 0
3 years ago
Please help me answer number 38.
julia-pushkina [17]

The request is to find the intersection of the two sets. By definition, the intersection of two sets is another set, composed by all the elements appearing in both sets.

In other words, P\cap Q is the set of all elements that P and Q have in common.

P contains all the numbers from 0 to 9, V contains all the odd numbers between 1 and 19. So, their intersection will be the odd numbers between 0 and 9, i.e.

P\cap Q=\{1, 3, 5, 7, 9\}

5 0
3 years ago
What are the solutions to the quadratic equation below in factored form?
saw5 [17]

Answer:

\cfrac{-4}{3} and \cfrac{1}{2}.

Step-by-step explanation:

Equation:

\rm \:  \: (2x - 1)(3x + 4) = 0

Solution:

Set factors equal to zero,that is:

(2x - 1) = 0 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: ...(1)

(3x + 4) = 0 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: ...(2)

Solving for equation 1:

  • 2x - 1 = 0
  • 2x = 0  + 1
  • 2x =  1

  • \boxed{x =  \cfrac{  1}{2} }

Solving for equation 2:

  • 3x + 4 = 0
  • 3x = 0 - 4
  • 3x =  - 4

  • \boxed{x =  \cfrac{ - 4}{3} }

Hence,the solutions to the quadratic equation in factored form is \cfrac{-4}{3} and \cfrac{1}{2}.

\rule{225pt}{2pt}

Good luck on your assignment!

4 0
2 years ago
Read 2 more answers
If a stadium has 15,000 seats sold at $10.00, $12.50, and $15.00 equally distributed in three sections, how much can be made if
ELEN [110]
If it is equally distrubuted in 3 sections then we would divide 15,000 by 3. Now we take one section which would cost $10.00 and multiply it by the 5,000 since we divided. We would do the same with all three and then add it together.

$10 * 5,000 = $50,000 section one can sell this much
$12.50 * 5,000 = $62,500 section two can sell this much
$15 * 5,000 = $75,000 section three can sell this much

If all the seats are sold than 50k + 62.5k + 75k = $187,500 can be made
3 0
3 years ago
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