What expression is equivalent to 8(5n)

Waterway Industries has fixed costs of $15,000 per year. Its warehouse sells wine with variable costs of 70% of its unit selling

vampirchik [111]

Answer:

50000 units sale per dollar price of the wine

Step-by-step explanation:

Fixed cost per year = $15,000

Variable cost per bottle of wine = 70% of selling price

To break even, the profits from the number of units sold = $15,000

(30% of selling price)× X units =$15,000

Or 15,000÷0.3 =50000 units per dollar price of wine

5 0

4 years ago

What is the circumference of the circle below? Use the formula C = 2tr.

alexandr1967 [171]

Answer: B

Step-by-step explanation:

The formula for circumference of a circle is 2 pie radius (2πr)

1. radius=5

2 so 2π(5)

3 2x5=10

4. 10π

5 0

3 years ago

Read 2 more answers

The following list details the numbers of tickets sold for a talent show grade 9:22; grade 10:32; grade 11: 41; and grade 12:30.

Montano1993 [528]

Answer: C. domain: {9, 10, 11, 12); range: (22, 32, 41, 30)

Step-by-step explanation:

The data set is:

(9, 22)

(10,32)

(11, 41)

(12, 30).

In the usual notation, the number at the left is the input (belons to the domain) and the number in the right is the output (belongs to the range).

Then the domain would be:

{9, 10, 11, 12}

and the range:

{22, 32, 41, 30}

The correct option is C

7 0

3 years ago

Element X is a radioactive isotope such that its mass decreases by 26% every day. If an experiment starts out with 810 grams of

ioda

Answer:

The hourly decay rate is of 1.25%, so the hourly rate of change is of -1.25%.

The function to represent the mass of the sample after t days is $A(t) = 810(0.74)^t$

Step-by-step explanation:

Exponential equation of decay:

The exponential equation for the amount of a substance is given by:

$A(t) = A(0)(1-r)^t$

In which A(0) is the initial amount and r is the decay rate, as a decimal.

Hourly rate of change:

Decreases 26% by day. A day has 24 hours. This means that $A(24) = (1-0.26)A(0) = 0.74A(0)$ ; We use this to find r.

$A(t) = A(0)(1-r)^t$

$0.74A(0) = A(0)(1-r)^{24}$

$(1-r)^{24} = 0.74$

$\sqrt[24]{(1-r)^{24}} = \sqrt[24]{0.74}$

$1 - r = (0.74)^{\frac{1}{24}}$

$1 - r = 0.9875$

$r = 1 - 0.9875 = 0.0125$

The hourly decay rate is of 1.25%, so the hourly rate of change is of -1.25%.

Starts out with 810 grams of Element X

This means that $A(0) = 810$

Element X is a radioactive isotope such that its mass decreases by 26% every day.

This means that we use, for this equation, r = 0.26.

The equation is:

$A(t) = A(0)(1-r)^t$

$A(t) = 810(1 - 0.26)^t$

$A(t) = 810(0.74)^t$

The function to represent the mass of the sample after t days is $A(t) = 810(0.74)^t$

5 0

3 years ago

Simplify: −3xy2(2x2y3 + 7xy2 − 5x3y2)

mestny [16]

collect the like terms

Answer is C

5 0

3 years ago