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2 years ago

can someone please help me with this please. I'm serious stuck on this what will I put for a? and b?

Mathematics

1 answer:

atroni [7]2 years ago

8 0

$21,400 \times 0.03 = 642$
$21,400 + 642 = 22,042$

OR
$21,400 \times 1.03 = 22,042$ same either way.

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Factor Polynomial 3y^2+y-14

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Answer:

Factored Form: ( y - 2 )( 3y + 7 )

Step-by-step explanation:

1. Let us first write down the problem at hand: 3y^2 + y - 14

2. Now let us break this expression into groups:

3y^2 - 6y + 7y - 14 ⇒ ( 3y^2 - 6y )( 7y - 14 )

3. Factor 3y from 3y^2 - 6y:

3y^2 - 6y ⇒ 3y( y - 2 )

4. Factor 7 from 7y - 14:

7y - 14 ⇒ 7( y - 2 )

5. Substitute Step #3, 4 ⇒ Step #2:

3y( y - 2 ) + 7( y - 2 )

6. Factor common term y - 2:

Answer: ( y - 2 )( 3y + 7 )

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3 years ago

Given: EFGH is a square Find the length of FH.

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Answer:

$1+r+r^{2}+r^{3}+.....+r^{n-1} = \frac{1-r^{n}}{1-r}$

Step-by-step explanation:

Taking the succession:

$1+r+r^{2}+r^{3}+.....+r^{n-1}$

You can multiply and divide by 1-r without chaging the result:

$\frac{1-r}{1-r} (1+r+r^{2}+r^{3}+.....+r^{n-1})$

Distributing the upper part of the fraction you have:

$\frac{1}{1-r} (1-r+r-r^{2}+r^{2}-r^{3}+r^{3}-r^{4}+.....+r^{n-1}-r^{n})$

As can be seen all the intermediate members will be canceled by a same member with opposite sign, only $(1-r^{n})$ will be left so:

$1+r+r^{2}+r^{3}+.....+r^{n-1} = \frac{1-r^{n}}{1-r}$

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