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Maurinko [17]
2 years ago
11

Write the first five terms of the sequence defined by the recursive formula

Mathematics
2 answers:
stepan [7]2 years ago
8 0

<u>Answer:</u>

The correct answer option is: S_9=\frac{9}{2} (2+26)

<u>Step-by-step explanation:</u>

We know that,

the sum of the first n terms of an Arithmetic Sequence is given by:

S_9=\frac{n(a_1+a_n)}{2}

where n is the number of terms,

a_1 is the first term of the sequence; and

a_n is the first term of the sequence.

So for a_n=3n-1,

a_1=3(1)-1=2

and

a_9=3(9)-1=26

Putting these values in the formula to get:

S_9=\frac{9(a_1+a_9)}{2}

S_9=\frac{9(2+26)}{2} \\\\S_9=\frac{9}{2} (2+26)

<u>First five terms:</u>

a_1=3(1)-1=2

S_1=\frac{1(2+2)}{2}=2


a_2=3(2)-1=5

S_2=\frac{2(2+5)}{2}=7


a_3=3(3)-1=8

S_2=\frac{3(2+8)}{2}=15


a_4=3(4)-1=11

S_4=\frac{4(2+11)}{2}=26


a_5=3(5)-1=14

S_5=\frac{5(2+14)}{2}=40



arlik [135]2 years ago
8 0

Answer: the corrrect one is A s9=9/2(2+26)


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