1) Formulas:
a) mole fraction of component 1, X1
X1 = number of moles of compoent 1 / total number of moles
b) Molar mass = number grams / number of moles => number of moles = number of grams / molar mass
2) Application
Number of moles of CaI2 = 0.400
Molar mass of water = 18.0 g/mol
Number of moles of water: 850.0 g / 18.0 g/mol = 47.22 mol
Total number of moles = 0.400 + 47.22 =47.62
Molar fraction of CaI2 = 0.400 / 47.62 = 0.00840
Answer:
<h2>14.05 moles</h2>
Explanation:
To find the number of moles in a substance given it's number of entities we use the formula

where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have

We have the final answer as
<h3>14.05 moles</h3>
Hope this helps you
metal rusting in salt water
Answer:
CuSO₄(aq) + 2KOH (aq) —> Cu(OH)₂(s) + K₂SO₄(aq)
Explanation:
CuSO₄ + 2KOH —> Cu(OH)₂ + K₂SO₄
To know the state of each compounds, we shall determine the complete ionic equation. This can be obtained as follow:
In solution, CuSO₄ and KOH will dissociate as follow:
CuSO₄(aq) —> Cu²⁺(aq) + SO₄²¯(aq)
KOH (aq) —> K⁺ (aq) + OH¯(aq)
CuSO₄(aq) + KOH (aq) —>
Cu²⁺(aq) + SO₄²¯(aq) + 2K⁺(aq) + 2OH¯(aq) —> Cu(OH)₂(s) + 2K⁺(aq) + SO₄²¯(aq)
Note: Cu(OH)₂ is insoluble in water.
Therefore, the elemental equation is:
CuSO₄(aq) + 2KOH (aq) —> Cu(OH)₂(s) + K₂SO₄(aq)
2:5 is the answer have a awesome day