What is the particular solution to the differential equation
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We have been given that in ΔJKL, the measure of ∠L=90°, KL = 22 feet, and JK = 54 feet. We are asked to find the measure of angle J to nearest degree.
First of all, we will draw a triangle as shown in the attachment.
We can see from our attachment that side KL is opposite side to angle J and side JK is hypotenuse of right triangle.
We know that sine relates opposite side of right triangle to hypotenuse.
Using inverse sine or arcsin, we will get:
Upon rounding to nearest degree, we will get:
Therefore, the measure of angle J is approximately 24 degrees.
