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3 years ago

Kendra used these steps to solve the equation 2x + 5 = 3 + 2(x + 1). Which choice describes the meaning of her result, 5 = 5?

1 answer:

5 0

Kendra's result is a "tautology", always true. Her equation will always be true, regardless of the value of x. It has an infinite number of solutions.

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Round 198 to the nearest ten and hundred

zzz [600]

Nearest 100: 200
nearest 10: 200

4 0

4 years ago

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Find the value of a and b if root3-1/root3+1+ root3+1/root3-1=a+root3 b

Digiron [165]

Answer:

a=4 and b = 0

Step-by-step explanation:

Given : $\dfrac{\sqrt 3 -1}{\sqrt 3+1}+\dfrac{\sqrt 3+1}{\sqrt 3-1}=a+\sqrt 3 b$

To find, The value of a and b

Solution,

Solving LHS of the given equation,

$\dfrac{(\sqrt 3-1)^2+(\sqrt3+1)^2}{(\sqrt 3+1)(\sqrt 3-1)}=a+\sqrt 3 b$

Since,

$(a-b)^2=a^2+b^2-2ab\\\\(a+b)^2=a^2+b^2+2ab\\\\(a-b)(a+b)=a^2+b^2$

So,

$\dfrac{3+1-2\sqrt 3+3+1+2\sqrt 3}{3-1}=a+\sqrt 3 b\\\\4=a+\sqrt 3 b$

$4+0=a+\sqrt 3 b$

On comparing we get :

a = 4 and b = 0

4 0

4 years ago

Each student in your class must do 14 homework problems. There are 23 students in the class. How many problems will your teacher

Ganezh [65]

Answer: 322

Step-by-step explanation:

23 students × 14 homework

=322 problems

The teacher will have to grade 322 problems

4 0

4 years ago

A population has a standard deviation of 5.5. What is the standard error of the sampling distribution if the sample size is 81?

VladimirAG [237]

Answer:

$\sigma = 5.5$

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution $\bar X$ and for this case we know that the distribution is given by:

$\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611$

Step-by-step explanation:

For this case we know the population deviation given by:

$\sigma = 5.5$

And we have a sample size of n =81. We want to estimate the standard error of the sampling distribution $\bar X$ and for this case we know that the distribution is given by:

$\bar X \sim N(\mu ,\frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$\sigma_{\bar x}= \frac{\sigma}{\sqrt{n}}$

And replacing we got:

$\sigma_{\bar x}=\frac{5.5}{\sqrt{81}}= 0.611$

4 0

3 years ago

How likely is it that you would push a green button if your eyes are closed

Harrizon [31]

Answer:

This really depends on the situation, and many variables. Is there a specific moment? Multiple buttons? Would you mind giving more context or is that it?

8 0

3 years ago

Read 2 more answers