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2 years ago

Which of the following describes the boundaries created by earth's tectonic systems

Chemistry

1 answer:

Dvinal [7]2 years ago

8 0

The earth's plates usually move in three different ways resulting in three different types of plate margins/ boundaries: CONVERGENT, DIVERGENT and TRANSFORM plate boundaries.

When plates move towards each other, they collide and this usually either results in the denser of the plates sliding below the other plate or both plates pushing against each other resulting in both plates being pushed upwards to form often times Fold Mountains. This type of earth tectonics causes a CONVERGENT (destructive; because the collision of the plates results in loss of earth surface area) plate boundary to be formed.

Plates can also pull away from each other and in so doing creating space usually in the form of a fissure between the two moving plates. This fissure usually also for molten earth (magma) rising to the surface and closing the opening between the plates. This type of earth tectonic is known to form DIVERGENT (constructive; because it usually results in new land being formed) plate margins.

Plates also slide against each other (side to side) thus not resulting in neither the destruction or creation of new land. This kind of plate margin is known as the TRANSFORM plate boundary.

The diagram below helps to solidify the points made above.

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Valeric acid, HC5H9O2 (Ka = 1.5 ✕ 10−5), is used in the manufacture of magnesium valerate, a nerve-calming agent. What is the hy

Studentka2010 [4]

Answer:

$[H^+]=0.00332M$

Explanation:

Hello,

In this case, considering the dissociation of valeric acid as:

$HC_5H_9O_2 \rightleftharpoons C_5H_9O_2 ^-+H^+$

Its corresponding law of mass action is:

$Ka=\frac{[H^+][C_5H_9O_2^-]}{[HC_5H_9O_2]}$

Now, by means of the change $x$ due to dissociation, it becomes:

$Ka=\frac{(x)(x)}{0.737-x}=1.5x10^{-5}$

Solving for $x$ we obtain:

$x=0.00332M$

Thus, since the concentration of hydronium equals $x$ , the answer is:

$[H^+]=x=0.00332M$

Best regards.

7 0

2 years ago

why is it harder to remove an electron from fluorine than from carbon? to put it another way, why are the outermost electrons of

Verizon [17]

It is harder to remove an electron from fluorine than from carbon because the size of the nuclear charge in fluorine is larger than that of carbon.

The energy required to remove an electron from an atom is called ionization energy.

The ionization energy largely depends on the size of the nuclear charge. The larger the size of the nuclear charge, the higher the ionization energy because it will be more difficult to remove an electron from the atom owing to increased electrostatic attraction between the nucleus and orbital electrons.

Since fluorine has a higher size of the nuclear charge than carbon. More energy is required to remove an electron from fluorine than from carbon leading to the observation that; it is harder to remove an electron from fluorine than from carbon.

Learn more: brainly.com/question/16243729

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2 years ago

Blank is the area of physical science that studies energy and how it acts with matter

Kobotan [32]

Answer:

Physics is a natural science that involves the study of matter and its motion through space and time, along with related concepts such as energy and force. More broadly, it is the study of nature in an attempt to understand how the universe behaves.

Explanation:

5 0

2 years ago

If a chemist has a stock solution of HBr that is 10.0 M and would like to make 450.0 mL of 3.0 M HBr, how would he do it?

asambeis [7]

This is a dilution that requires a certain volume from the stock solution to be diluted with distilled water to make a solution of HBr with a lesser concentration than the stock solution

Following dilution formula can be used

c1v1 = c2v2

Where c1 is concentration and v1 is the volume of the stock solution

c2 is concentration and v2 is volume of the diluted solution to be prepared

Substituting these values

10.0 M x v1 = 3.0 x 450.0 mL

v1 = 135.0 mL

A volume of 135.0 mL from HBr stock solution needs to be taken and diluted with distilled water upto 450.0 mL. The resulting solution will have a concentration of 3.0 M

4 0

2 years ago

What element is helpful for tooth decay

emmainna [20.7K]

Fluoride and calcium are both helpful for stopping tooth decay

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3 years ago