Answer:
Explanation:
Hello,
The six-carbon benzene ring contains two types of bonds: C-C and C-H bonds, that are -hybridized σ bonds, and the six π bonds that form the aromatic ring. The σ bonds form from one 
orbital and two 
orbitals from each carbon, which then bond the carbon to the two carbons on either side and the carbon's single hydrogen. The remaining orbital from each carbon atom sticks out above and below the plane of the ring; these orbitals overlap sideways, rather than lengthwise, to form the aromatic π bond system.
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Inherited it from his grandfather
Answer:
1.47 atm
Explanation:
Step 1: Given data
- Initial volume (V₁): 32.4 L
- Initial pressure (P₁): 1 atm (standard pressure)
- Initial temperature (T₁): 273 K (standard temperature)
- Final volume (V₂): 28.4 L
- Final temperature (T₂): 352 K
Step 2: Calculate the final pressure of the gas
We can calculate the final pressure of the gas using the combined gas law.
P₁ × V₁ / T₁ = P₂ × V₂ / T₂
P₂ = P₁ × V₁ × T₂ / T₁ × V₂
P₂ = 1 atm × 32.4 L × 352 K / 273 K × 28.4 L = 1.47 atm
0.000735 in scientific notation is 7.35 x 10^-4
