Question

An Alaskan rescue plane traveling 46 m/s drops a package of emergency rations from a height of 101 m to a stranded party of explorers. The acceleration of gravity is 9.8 m/s^2. Where does the package strike the ground relative to the point directly below where it was released? Answer in units of m.

Answer 1

Answer:

The package strikes 207 m at the ground relative to the point.

Explanation:

Given that,

Speed = 46 m/s

Height = 101 m

Acceleration = 9.8 m/s²

We need to calculate the time

Using equation of motion

$s=ut+\dfrac{1}{2}gt^2$

Put the value in the equation

$101=0+\dfrac{1}{2}\times9.8\times t^2$

$t=\sqrt{\dfrac{2\times101}{9.8}}$

$t=4.5\ sec$

We need to calculate the distance where the package strikes

Using formula of distance

$x=vt$

Put the value into the formula

$x=46\times4.5$

$x=207\ m$

Hence, The package strikes 207 m at the ground relative to the point.