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kicyunya [14]
3 years ago
7

A student pushes on a crate with the force of 100 Newtons directed to the right. What force does the crate exert on the student?

Note: It has to be done with the Newton's 2nd Law of Motion.
Physics
1 answer:
ale4655 [162]3 years ago
6 0

Answer: The Force exerted on the student by crate will be 100 N.

Explanation: As per the given Question student is trying to push the crate in right direction with the force of 100N.

And we know that, Newton's third law states that every action has equal and opposite reaction.

So from the Newton's 3rd law of motion it is very clear the student must be experiencing the same amount of force which he is applying.

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According to Kepler's Third Law, a solar-system planet that has an orbital radius of 4 AU would have an orbital period of about
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Orbital period, T = 1.00074 years

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Orbital radius of a solar system planet, r=4\ AU=1.496\times 10^{11}\ m

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T^2=\dfrac{4\pi^2}{6.67\times 10^{-11}\times 1.989\times 10^{30}}\times (1.496\times 10^{11})^3    

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T = 31559467.6761 s

T = 1.00074 years

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6 0
3 years ago
A 100-kg running back runs at 5 m/s into a stationary linebacker. It takes 0.5 s for the running back to be completely stopped.
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Answer:

1000 N

Explanation:

First, we need to find the deceleration of the running back, which is given by:

a=\frac{v-u}{t}

where

v = 0 is his final velocity

u = 5 m/s is his initial velocity

t = 0.5 s is the time taken

Substituting, we have

a=\frac{0-5 m/s}{0.5 s}=-10 m/s^2

And now we can calculate the force exerted on the running back, by using Newton's second law:

F=ma=(100 kg)(-10 m/s^2)=-1000 N

so, the magnitude of the force is 1000 N.

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sim eu também preciso desta respota

7 0
2 years ago
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