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3 years ago

1. Rocks change as a result of what?

Physics

2 answers:

lisov135 [29]3 years ago

3 0

1.Erosion 2.by color,texture etc

aliina [53]3 years ago

3 0

Answer by YourHope:

Hi! :)

1. Rocks change as a result of Erosion!

2. Rocks are sorted by color and texture!

3. Melted rock deep in the earth is called magma!

4. The process that occurs when melted rock cools is called igneous rock!

5. How does the rate of Cooling affect crystal formation in rocks? It affects the size of the crystals that form within each of the solid rocks. Rapid cooling produces small crystals, while slower cooling producing larger ones!

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3 years ago

Read 2 more answers

The acceleration due to the earth's gravity, in si units, is 9.8 m/s2. in the absence of air friction, a ball is dropped from re

gogolik [260]

We don't know anything about the amount of distance it travels, but that's okay. The only equation we need here is

velocity(final) = velocity(initial) + acceleration * time
vf = vi + (a * t)

The ball is dropped from rest, so vi = 0 m/s.
We want it so that the ball hits the ground with a final velocity of 60 m/s, so vf = 60 m/s.
We are given the acceleration due to gravity, a = 9.8 m/s^2.
We are solving for the time, t = ?.

Now we just plug in the values.
vf = vi + (a * t)
60 m/s = 0 m/s + (9.8 m/s^2)*(t)

60 = 9.8t

60 / 9.8 = t

t = 6.122 s

Hopefully this is the right answer.

7 0

3 years ago

A student walks (2.9±0.1)m, stops and then walks another (3.9 ±0.2)m in the same directionWith the given uncertainties, what is

Anika [276]

Answer:

The smallest distance the student that the student could be possibly be from the starting point is 6.5 meters.

Explanation:

For 2 quantities A and B represented as

$A\pm \Delta A$ and $B\pm \Delta B$

The sum is represented as

$Sum=(A+B)\pm (\Delta A+\Delta B)$

For the the values given to us the sum is calculated as

$Sum=(2.9+3.9)\pm (0.1+0.2)$

$Sum=6.8\pm 0.3$

Now the since the uncertainity inthe sum is $\pm 0.3$

The closest possible distance at which the student can be is obtained by taking the negative sign in the uncertainity

Thus closest distance equals $6.8-0.3=6.5$ meters

3 0

3 years ago

A wall with a surface area of 10 m2 is 2.5 cm thick. The inner surface temperature of the wall is 4150C, but the outer surface i

klio [65]

Answer:

650.65 K or 377.5°C

Explanation:

Area = A = 10 m²

Thickness of wall = L = 2.5 cm = 2.5×10⁻² m

Inner surface temperature of wall = $T_i$ = 415°C = 688.15 K

Outer surface temperature of wall = $T_o$

Heat loss through the wall = 3 kW = 3×10³ W

Thermal conductivity of wall = k = 0.2 W/m K

Assumptions made here as follows

There is not heat generation in the wall itself
The heat conduction is one dimensional
Heat flow follows steady state
The material has same properties in all directions i.e., it is homogeneous.

Considering the above assumptions we use the following formula

$Q=\frac {T_i-T_o}{\frac{L}{kA}}\\\Rightarrow T_o=T_i-\frac {QL}{kA}\\\Rightarrow T_o=688.15-\frac {3\times 10^{3}\times 2.5\times 10^{-2}}{0.2\times 10}\\\Rightarrow T_o=650.65~K$

∴ The temperature of the outer surface of the wall is 650.65 K or 377.5°C

5 0

3 years ago