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hjlf
3 years ago
10

What is the concentration of water in liquid (Percent)

Chemistry
1 answer:
scZoUnD [109]3 years ago
6 0

Hello!

Reading the worksheet shows you how to find the concentration of liquid water in a substance, but when converting a decimal to a percentage, remember that ALL percentages are out of 100, so, we multiply the decimal by 100 to convert it into a percentage.

Liquid A: total amount: 10 millimeters & amount of water: 7 millimeters

7/10 = 0.7 × 100 = 70%

Liquid B: total amount: 100 millimeters & amount of water: 92 millimeters

92/100 = 0.92 × 100 = 92%

Liquid C: total amount: 15 millimeters & amount of water: 13 millimeters

13/15 = 0.867 × 100 = 86.7%

Liquid D: total amount: 28 millimeters & amount of water: 22 millimeters

22/28 = 0.786 × 100 = 78.6%

<u>Final answers</u>:

  • Liquid A: 70%
  • Liquid B: 92%
  • Liquid C: 86.7%
  • Liquid D: 78.6%
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The equation is given is of combustion of ethanol.

Fuel ethanol (C2H5OH) has high energy carbon-carbon (C-C) and carbon-hydrogen (C-H) bonds that store chemical energy. From the ethanol container, ethanol molecules evaporating, enter the flame's base. A physical action called evaporation converts liquid into gas. Ethanol evaporates with a constant molecular structure.

The molecules of ethanol and oxygen combine inside the flame and undergo a chemical transformation. Let's consider matter, or the atoms. The oxygen (O2) and ethanol (C2H5OH) molecules' atoms reorganise into carbon dioxide (CO2) and water (H2O). There are always the same number of atoms. A chemical equation may be used to demonstrate how the atoms are rearranged.

Energy is released as the atoms in the oxygen and ethanol are rearranged. When the high-energy C-C and C-H bonds in ethanol are swapped out for the low-energy H-O and C=O bonds in carbon dioxide and water, chemical energy is released as heat and light.

The ethanol and oxygen atoms are rearranged into carbon dioxide and water during burning. Water and carbon dioxide escape from the flame's top.

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<u>Answer:</u> The pH of the solution is 1.41

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

Given mass of perchloric acid = 581.1 mg = 0.5811 g   (Conversion factor:  1 g = 1000 mg)

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Putting values in above equation, we get:

\text{Molarity of perchloric acid}=\frac{0.5811\times 1000}{100.5\times 150}\\\\\text{Molarity of perchloric acid}=0.0385M

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To calculate the pH of the solution, we use the equation:

pH=-\log[H^+]

We are given:

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Putting values in above equation, we get:

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