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4 years ago

Why does a catalyst work for a long time before it needs replacing?

1 answer:

7 0

Because the catalyst is not really part of the reaction. it is something that speed up a reaction by lowering the energy need for the reaction to take place. however, in the end the catalyst is brought back to its initial state. that's why it is long lasting

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Pine trees slightly prefer slightly acidic soil. What happens if the pH changes to above 7?

egoroff_w [7]

Answer:

The trees' growth might be affected

Explanation:

A pH above 7 indicates that the soil is no more acidic and that it had turned basic or alkaline in nature. This may affect the functioning of enzymes as this value is very far from optimum pH value. Thus growth is affected.

7 0

3 years ago

Read 2 more answers

Write a balanced equation for the following neutralization reaction HBr+LiOH<->

Sophie [7]

Answer:

HBr(aq) + LiOH(aq) = LiBr(aq) + H2O(l)

Explanation:

For this reaction, the reactants are the hydrobomic acid and the lithium hydroxide which produces the products lithium bromide and water.

8 0

3 years ago

Plz Help Me

Rasek [7]

Answer:- The wavelength is $1.36*10^1^2m$ and the right option is D.

Solution:- Wavelength is inversely proportional to the frequency and the equation is:

$\lambda =\frac{c}{\nu }$

where, $\lambda
$ is the wavelength, c is the speed of light and $\nu$ is frequency.

Frequency is $2.20*10^-^4Hz$ and the speed of light is $3.00*10^8\frac{m}{s}$ .

Since, $1Hz=1s^-^1$

So, $2.20*10^-^4Hz=2.20*10^-^4s^-^1$

Let's plug in the values in the equation:

$\lambda =\frac{3.00*10^8m.s^-^1}{2.20*10^-^4s^-^1}$

$\lambda =1.36*10^1^2m$

Hence, the right option is D) $1.36*10^1^2m$ .

7 0

3 years ago

Read 2 more answers

odium carbonate (Na2CO3Na2CO3) is used to neutralize the sulfuric acid spill. How many kilograms of sodium carbonate must be add

Arte-miy333 [17]

Answer : The mass of sodium carbonate added to neutralize must be, $6.54\times 10^3kg$

Explanation :

First we have to calculate the moles of $H_2SO_4$ .

$\text{Moles of }H_2SO_4=\frac{\text{Mass of }H_2SO_4}{\text{Molar mass of }H_2SO_4}$

Given:

Molar mass of $H_2SO_4$ = 98 g/mole

Mass of $H_2SO_4$ = $6.05\times 10^3kg=6.05\times 10^6g$

Conversion used : (1 kg = 1000 g)

Now put all the given values in the above expression, we get:

$\text{Moles of }H_2SO_4=\frac{6.05\times 10^6g}{98g/mol}=6.17\times 10^4mol$

The moles of $H_2SO_4$ is, $6.17\times 10^4mol$

Now we have to calculate the moles of $Na_2CO_3$

The balanced neutralization reaction is:

$Na_2CO_3+H_2SO_4\rightarrow Na_2SO_4+H_2CO_3$

From the balanced chemical reaction we conclude that,

As, 1 mole of $H_2SO_4$ neutralizes 1 mole of $Na_2CO_3$

So, $6.17\times 10^4mol$ of $H_2SO_4$ neutralizes

Now we have to calculate the mass of $Na_2CO_3$

$\text{ Mass of }Na_2CO_3=\text{ Moles of }Na_2CO_3\times \text{ Molar mass of }Na_2CO_3$

Molar mass of $Na_2CO_3$ = 106 g/mole

$\text{ Mass of }Na_2CO_3=(6.17\times 10^4mol)\times (106g/mole)=6.54\times 10^6g=6.54\times 10^3kg$

Thus, the mass of sodium carbonate added to neutralize must be, $6.54\times 10^3kg$

3 0

4 years ago

Describe the composition of the nucleus of an atom. A) It is composed of protons. B) It is composed of protons and neutrons. C)

Kryger [21]

He atom<span> consists of a tiny </span>nucleus<span> surrounded by moving electrons. </span>

3 0

3 years ago

Read 2 more answers