1 electron has charge =1.602* 10⁻¹⁹ C
1 mole of electrons have 1.602* 10⁻¹⁹*6.02*10²³C = 9.64*10⁴ C/1mol
One ion Co²⁺ takes 2e⁻ to become Co⁰.
1 mol of Co²⁺ ions take 2 mole of e⁻ to become Co⁰, so
0.30 mol Co²⁺ ions take mole of 0.60 mol e⁻ to become Co⁰
9.64*10⁴(C/1mol) *0.60 (mol)≈ 5.8 *10⁴ Coulombs.
Correct answer is C
Given :
Moles of Na : 1.06
Moles of C : 0.528
Moles of O : 1.59
To Find :
The empirical formula of the compound.
Solution :
Dividing moles of each atom with the smallest one i.e 0.528 .
So,
Na : 1.06/0.528 = 2.007 ≈ 2
C : 0.528/0.528 = 1
O : 1.59/0.528 = 3.011 ≈ 3
Rounding all them to nearest integer, we will get the number of each atom in the empirical formula.
So, empirical formula is 
.
Hence, this is the required solution.
Answer:
B. It is a nonliving resource.
Explanation:
The definition of abiotic is "nonliving," and examples of abiotic resources may include soil or water.
Answer:
Whereas solar energy makes use of the sun to generate energy, geothermal energy makes use of the heat that is trapped deep in the center of the earth. The magma buried deep down of our soil is as hot as the sun’s surface, and some of that heat manages to escape outward. When that happens, we can harness that said heat for energy.
Explanation:
The balanced reaction is 3
Ca
(
s
)
+
N
2
(
g
) → Ca
3
N
2
(
s
).
<u>Explanation</u>:
A chemical equation is said to be balanced when the total number of atoms present on the reactants side is equal to the total number of atoms present on the product side.
The unbalanced chemical equation is as follows,
Ca
(
s
)
+
N
2
(
g
) → Ca
3
N
2
(
s
)
To balance this equation, you need to look at how many atoms of each element are present on each side of the chemical equation.
Calcium has 1 atom on the reactant and 3 on the products side. To balance the reaction we need to multiply the calcium atom by 3 on the reactants side.
3
Ca
(
s
)
+
N
2
(
g
) → Ca
3
N
2
(
s
)
Now Nitrogen has a coefficient of 2 on both sides of the reaction. Hence the balanced chemical equation will thus be
3
Ca
(
s
)
+
N
2
(
g
) → Ca
3
N
2
(
s
)
