Can you provide a picture
The chemical formula of fructose is C6H12O6
I personally, would remove " Lamp oil is a very polar substance " And replace it with what the article you wrote, was about. For example, lets say you wrote about why people love ice cream, you could have the ending sentence say. " And that's why I wrote about why people love ice cream" Or something along those lines. I'd write a few more facts about it first, don't just have one sentence saying a fact without any supporting detail, hope this helps! :)
Answer:
a)If concentration of [Sucrose] is changed to 2.5 M than rate will be increased by the factor of 2.5.
b)If concentration of [Sucrose] is changed to 0.5 M than rate will be increased by the factor of 0.5.
c)If concentration of is changed to 0.0001 M than rate will be increased by the factor of 0.01.
d) If concentration when [sucrose] and both are changed to 0.1 M than rate will be increased by the factor of 1.
Explanation:
Sucrose + fructose+ glucose
The rate law of the reaction is given as:
[sucrose]= 1.0 M
..[1]
a)
The rate of the reaction when [Sucrose] is changed to 2.5 M = R'
..[2]
[2] ÷ [1]
If concentration of [Sucrose] is changed to 2.5 M than rate will be increased by the factor of 2.5.
b)
The rate of the reaction when [Sucrose] is changed to 0.5 M = R'
..[2]
[2] ÷ [1]
If concentration of [Sucrose] is changed to 0.5 M than rate will be increased by the factor of 0.5.
c)
The rate of the reaction when is changed to 0.001 M = R'
..[2]
[2] ÷ [1]
If concentration of is changed to 0.0001 M than rate will be increased by the factor of 0.01.
d)
The rate of the reaction when [sucrose] and both are changed to 0.1 M = R'
..[2]
[2] ÷ [1]
If concentration when [sucrose] and both are changed to 0.1 M than rate will be increased by the factor of 1.
Answer: when a system reaches equilibrium, the rate of formation of product equals the rate of formation of reactant. At this state, we say the reaction is in dynamic equilibrium. Therefore the rate of formation of product and the rate of formation of reactant are equal
Explanation: