Given:
t A = 2.4 h
t B = 4 h
v A = 22 + v B
Solution:
Distance A and distance B is the same, distance could be defined using formula d = v × t
d A = d B
(v A × t A) = (v B × t B)
plug in the numbers
v A × 2.4 = v B × 4
(22 + vB) × 2.4 = 4 vB
remove the parenthesis using distributive property
(22 × 2.4) + (2.4 × vB) = 4vB
52.8 + 2.4vB = 4vB
add like terms
52.8 = 4vB - 2.4vB
52.8 = 1.6vB
52.8/1.6 = vB
vB = 33
the speed of car B is 33 mph
vA = 22 + vB
vA = 22 + 33
vA = 55
the speed of car A is 55 mph
<h3>I'll teach you how to solve (1/5x-4+2y)+(2/5x+5-4y)</h3>
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(1/5x-4+2y)+(2/5x+5-4y)
Remove parentheses:
1/5x-4+2y + 2/5x+5-4y
Group like terms:
1/5x+2/5x+2y-4y-4+5
Add similar elements:
3/5x+2y-4y-4+5
Add similar elements:
3/5x-2y-4+5
Multiply:
3x/5-2y-4+5
Add subtract the numbers:
3x/5+1-2y
Your Answer Is 3x/5+1-2y
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can you show me a picture then maybe i can help you
Answer:
3
y
(
2
x
−
1
)
(
x
−
4
y
)
Step-by-step explanation:
The blank is 123 because 32/41=96/123.
your multiplying 32 by 3 to get 96.
That means you have to multiply the bottom by 3 too.
41 multiplied by 3 is 123.
And 123 is the blank.
