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3 years ago

The total surface area of a cube is 1734 in squared. What is the length of each side of the cube?

Mathematics

1 answer:

Sindrei [870]3 years ago

7 0

Answer:

1734

Step-by-step explanation:

1734

if you want you can give me brainlest

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When 250 students were interviewed, 96 of the students thought USC was the best school in the nation. The probability that one o

melomori [17]

Answer:

240/96.

Step-by-step explanation:

250-96 =240 so that's 240/96

3 0

3 years ago

Need help any body help please

lutik1710 [3]

For the first one (aka 7) you would write 10² wich is the same as 10×10 and so the answer is 100

For the second one (aka 8) you would write 3×3×3×3×3×3×3×3×3 and the answer is 486 square miles

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3 years ago

Q5: The probability that event A occurs is 5/7 and the probability that event B occurs is 2/3 . If A and B are independent event

bekas [8.4K]

Answer:

$P(A \cap B)$

And we can use the following formula:

$P(A \cap B)= P(A)* P(B)$

And replacing the info we got:

$P(A \cap B) = \frac{5}{7} \frac{2}{3}= \frac{10}{21}=0.476$

Step-by-step explanation:

We define two events for this case A and B. And we know the probability for each individual event given by the problem:

$p(A) = \frac{5}{7}$

$p(B) = \frac{2}{3}$

And we want to find the probability that A and B both occurs if A and B are independent events, who menas the following conditions:

$P(A|B) = P(A)$

$P(B|A) = P(B)$

And for this special case we want to find this probability:

$P(A \cap B)$

And we can use the following formula:

$P(A \cap B)= P(A)* P(B)$

And replacing the info we got:

$P(A \cap B) = \frac{5}{7} \frac{2}{3}= \frac{10}{21}=0.476$

7 0

3 years ago

How many packets of sugar and salt are in a standard Hershey's bar?

Arisa [49]

Answer:

there are 35 mg's of sodium/salt and 24 g's of sugar, therefore there is 67.2 packets of sugar and 9450 packets of salt

Step-by-step explanation:

im sorry if its wrong, it is what the calculator said!

8 0

2 years ago

Aisle 2 of a furniture store stocks 4-legged chairs, 4-legged tables, and 3-legged stools. If there are t tables, c chairs, and

aev [14]

Answer:

$T=4c+4t+3s$

Step-by-step explanation:

Stocks contains:

4-legged chairs

4-legged tables

3-legged stools

So, 1 chair has legs = 4

So, c chairs has legs = 4c

1 table has legs = 4

So, t tables has legs = 4t

1 stool has legs = 3

So, s stools has legs = 3s

Let T denotes the total no. of legs

So, the total number of furniture legs in aisle 2 :

$T=4c+4t+3s$

Hence $T=4c+4t+3s$ expression show the total number of furniture legs in aisle 2

7 0

3 years ago